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liraira [26]
4 years ago
14

In a certain quiz that consists of 10 questions, each question after the first is worth 4 points more than the preceding questio

n. If the 10 questions on the quiz are worth a total of 360 points, how many points is the third question worth?
A. 18
B. 24
C. 26
D. 32
E. 44
Mathematics
1 answer:
Artyom0805 [142]4 years ago
7 0

Answer:  The correct option is

(C) 26.

Step-by-step explanation: Given that in a certain quiz that consists of  10 questions, each question after the first is worth 4 points more than the preceding question.

All  the 10 questions on the quiz are worth a total of 360 points.

We are to find the worth of the third question in points.

Since each question after the first is worth 4 points more than the preceding question, so this will make an arithmetic sequence with

first term a, common difference, d = 4  and number of terms, n = 10.

We know that, in an A.P. with first term a and common difference d,

\textup{nth term, }a_n=a+(n-1)d,\\\\\textup{sum of first n terms, }S_n=\dfrac{n}{2}\{2a+(n-1)d\}.

According to the given information,

\textup{sum of first 10 terms, }S_n=360\\\\\Rightarrow \dfrac{10}{2}\{2a+(10-1)4\}=360\\\\\Rightarrow 5(2a+36)=360\\\\\Rightarrow 10(a+18)=360\\\\\Rightarrow a+18=36\\\\\Rightarrow a=36-18\\\\\Rightarrow a=18.

Therefore, the third term of the sequence is

a_3=a+(3-1)d=18+2\times4=18+8=26.

Thus, the third question worth 26 points.

Option (C) is CORRECT.

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During the summer holidays sarah earns pocket money by mowing lawn. She can mow 6 lawns in 1 1/2 and clean the pool in one-sixth
tigry1 [53]

Answer:

It will take Sarah 2 1/2 hours to mow 10 lawns

It will take Sarah 1 2/3 hours to clean 10 pools

Step-by-step explanation:

During the summer holidays, Sarah earns pocket money by mowing the lawn. She can mow 6 lawns in 1 1/2 hour and clean a pool in one-sixth of an hour. How long does Sarah take to clean 10 pools and 10 lawns?

Number of lawns : Time to mow lawns = 6 : 1 1/2

= 6 : 3/2

Number of lawns : Time to mow lawns = 10 : x

6 : 3/2 = 10 : x

6 ÷ 3/2 = 10/x

6 * 2/3 = 10/x

12/3 = 10/x

Cross product

12 * x = 3 * 10

12x = 30

x = 30/12

x = 2 6/12

x = 2 1/2 hours

It will take Sarah 2 1/2 hours to mow 10 lawns

Number of pools cleaned : time taken = 1 : 1/6

Number of pools cleaned : time taken = 10 : x

1 : 1/6 = 10 : x

1 ÷ 1/6 = 10/x

1 * 6/1 = 10/x

6 = 10/x

Cross product

6 * x = 10

6x = 10

x = 10/6

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x = 1 2/3 hours

It will take Sarah 1 2/3 hours to clean 10 pools

3 0
3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
4 years ago
For an oblique rectangular prism, find the volume if the height is divided up into 30 sections, with a total height of h = 60cm,
ladessa [460]

Answer:

Volume of a prism =BH

(length ×width)×height  

(10×20)×60

=12000cm3

Step-by-step explanation:

7 0
3 years ago
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