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denis-greek [22]
3 years ago
14

Graph the function.

Mathematics
2 answers:
liubo4ka [24]3 years ago
5 0
The answer is totally D
kap26 [50]3 years ago
4 0

Answer:

The correct option is D.

Step-by-step explanation:

If a line passing through two points, then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

From the given graph it is clear that the line is passing through the points (-1,2) and (0,-1), so the equation of line is

y-2=\frac{-1-2}{0-(-1)}(x-(-1))

y-2=-3(x+1)

y-2=-3x-3

y=-3x-3+2

y=-3x-1

The correct formula for the function is y=-3x-1, therefore the correct option is D.

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Each lap around a park is 1 1⁄5 miles. Kellyn plans to jog at least 7 1⁄2 miles at the park without doing partial laps. How many
Nitella [24]
1 1/5 can be written as 6/5
7 1/2 can be written as 15/2
Let X be the number of laps Kellyn wants to jog to meet her 7 1/2 mile goal:
6/5x = 15/2                Multiply both sides by (5/6), the inverse of 6/5
x = 15(5) / 2 ( 6) 
x = 75 / 12
X = 25 / 4, or 6 and 1/4 laps

6 0
3 years ago
Read 2 more answers
Evaluate the expression below if m = 350.<br><br> 3.5m =
Lena [83]

Answer:

1,225

Step-by-step explanation:

3.5×350=1225

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8 0
3 years ago
Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun
WITCHER [35]

Answer:

Required solution (a) f(x,y,z)=xyz+3z^2+C (b) 40.

Step-by-step explanation:

Given,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k

(a) Let,

F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}

Then,

f_x=yz,f_y=xz,f_z=xy+6z

Integrating f_x we get,

f(x,y,z)=xyz+g(y,z)

Differentiate this with respect to y we get,

f_y=xz+g'(y,z)

compairinfg with f_y=xz of the given function we get,

g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)

Then,

f(x,y,z)=xyz+h(z)

Again differentiate with respect to z we get,

f_z=xy+h'(z)=xy+6z

on compairing we get,

h'(z)=6z\implies h(z)=3z^2+C   (By integrating h'(z))  where C is integration constant. Hence,

f(x,y,z)=xyz+3z^2+C

(b) Next, to find the itegration,

\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40

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3 years ago
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