How to estimate the product of 3.4 x 5.6

Mathematics

1 answer:

Ghella [55]4 years ago

7 0

You would estimate 3.4 down to 3 and 5.6 up to 6. So you would do 3 times 6=18

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A page should have perimeter of 42 inches. The printing area within the page

Tamiku [17]

Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .

Step-by-step explanation:

We have , A page should have perimeter of 42 inches. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1.5 inches from each side. let's assume width of the page be x inches and its length be y inches So,

Perimeter = 42 inches

⇒ $2(x+y) = 42\\x+y = 21\\y = 21-x$

width of printed area = x-3 & length of printed area = y-2:

area = $length(width)$

$area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57$

Let's find $\frac{d(area)}{dx}$ :

$\frac{d(area)}{dx}$ = $\frac{d(-x^{2}+22x-57)}{dx} = -2x +22$ , for area to be maximum $\frac{d(area)}{dx}$ = 0

⇒ $-2x+22 = 0\\2x =22\\x=11 inches$

And ,

$y = 21-x\\y = 21-11\\y = 10 inches$

∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .

7 0

3 years ago

At LaGuardia Airport for a certain nightly flight, the probability that it will rain is 0.17 and the probability that the flight

mezya [45]

Answer:

100 - (Probability for raining + Probability for fight delay + Probability for Raining and fligth delay ) = Probability for no rain and flight on time.

So, 100-(0.17+0.16+0.07) = Probability for no rain and flight on time.

100-(0.40) = Probability for no rain and flight on time.

99.60=Probability for no rain and flight on time.

3 0

3 years ago

Simplify. Thank you...

Verizon [17]

Answer:

I'm not entirely sure but I got:

$\frac{ {4x}^{3} + 3 }{(2x - 1)( {x}^{2} + x)( {2x}^{2} - 3x + 1) }$