Answer:
H0: p(1980) = p(2010) ; H1 : P(1980) > P(2010)
0.02
Step-by-step explanation:
Given that:
Sample size in both 1980 and 2010 = 1000 samples :
Proportion in favor :
P(1980) = 0.66
P(2010) = 0.64
To test the hypothesis :
Null hypothesis :
Proportion in favor are the same in both years
Null hypothesis = H0 = p(1980) = p(2010)
Alternative hypothesis :
Proportion in favor in 1980 is greater than that in 2010
Alternative hypothesis = H1 : P(1980) > P(2010)
The sample statistic :
P(1980) - p(2010)
0.66 - 0.64
= 0.02
Boy: x
girl: x - 53
father: 4(x - 53)
Now you simplify.
The answer for the nearest 0.05 of 82 would be 1640
