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lubasha [3.4K]
3 years ago
10

PLSSS HELP State the maximum number of turns the graph of each function could make 1. f(x)=x^5-3x+1 2.f(x)=-x^7-7x^5-4x^3

Mathematics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

  1. max for 5th-degree: 4 turns. This function: 2 turns.
  2. max for 7th-degree: 6 turns. This function: 0 turns.

Step-by-step explanation:

In general, the graph of an n-th degree function can make n-1 turns. However, in specific cases, the number of turns is limited by the number of real zero-crossings of the derivative.

__

1. This 5th-degree function can have at most 4 turns. However, the derivative, f'(x) = 5x^4 -3, has only two (2) real zeros. Hence the graph of this function can only have 2 turns.

__

2. This 7th-degree function can have at most 6 turns. However, the derivative, f'(x) = -7x^6 -35x^4-12x^2, has an even-multiplicity root at x=0 only. The derivative never crosses 0. Hence the graph makes no turns.

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Rewrite the expression as a product of two factors. 72t+8
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Step-by-step explanation:

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5 0
3 years ago
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jek_recluse [69]
What the heckk??????????
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Help!! I need help!<br>​
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———————-

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—-   ——

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Don't stress anymore I'm here to help in online mathematics classes I have a doctorate degree in maths​
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Then I'll definitely will ask you questions about maths :)

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Read 2 more answers
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