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SCORPION-xisa [38]
3 years ago
13

Can someone help me solve these.

Mathematics
1 answer:
vazorg [7]3 years ago
4 0

(x-1)/-3 = (x+5)/6

You want to get x by itself. Start by multiplying both sides by -3 and 6:

6(x-1) = -3(x+5)

Distribute:

6x - 6 = -3x + 5

Add 6 and 3x to both sides:

6x + 3x = 5 + 6

9x = 11

Divide both sides by 9 to get x by itself:

x = 11/9

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Answer:

natasha paid the least amount

5 0
3 years ago
Look at the table. Make a conjecture about the sum of the first 15 positive even numbers.
Olenka [21]
Be observing the table, we can write the following conjecture:

When adding consecutive even numbers, starting from 2 to m.

Then the sum is equal to: 
\frac{m}{2}( \frac{m}{2} +1)

Then, the sum of the first 15 positive even numbers (which is the sum of 2 to 30) can be calculated with the previous conjecture by setting m=30:
\frac{m}{2}( \frac{m}{2} +1)=\frac{30}{2}( \frac{30}{2} +1)=(15)(16)=240

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4 0
4 years ago
A man is distributing his coin collection with 35 coins to his five grandchildren. How many ways are there to distribute the coi
Musya8 [376]

Answer:

a) 82251

b) 2.91038 \cdot 10^{24}

c) 1

d) 3.17746\cdot 10^{21}

Step-by-step explanation:

a) If the coins are all the same, we have a combination of 35 identical coins in 5 persons.

The amount of combinations is

\binom{n+r-1}{r-1}=\binom{35+5-1}{5-1}=\binom{39}{4}=\frac{39!}{4!35!} =82251

being n the number of coins and r the number of grandchildren.

b) If the coins are different, the number of combinations can be calculated as:

r^n=5^{35}=2.91038 \cdot 10^{24}

c) If the coins are all the same, and each grandchild gets the same number of coins, there is only one combination for that (everyone gets 35/5=7 coins)

d)  If the coins are all distinct, but each of the grandchildren get the same numer of coins, the expression to calculate this is:

\frac{n!}{(n/r)!^r} =\frac{35!}{(35/5)!^5}=\frac{35!}{7!^5}=\frac{1.03331\cdot 10^{40}}{3.25202\cdot 10^{18}} =3.17746\cdot 10^{21}

3 0
3 years ago
Kobe wants to purchase 8 marbles from the store. Each marble costs $.29, he has $2.00 in his pocket. Does kobe have enough money
tatiyna

Answer:

No

Step-by-step explanation:

8 marbles cost $2.32. He needs 32 more cents.

3 0
3 years ago
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