All categories

2 years ago

In a triangle, one of the angle measures 70°

Mathematics

1 answer:

Tanya [424]2 years ago

4 0

Answer:

the two angles are 55° each

Step-by-step explanation:

Let the two equal angles be y each

Therefore,

70° + y + y = 180°

Collect like terms

2y = 180 — 70

2y = 110

Divide both side by the coefficient of y i.e 2

y = 110/2

y = 55°

Therefore, the two angles are 55° each

You might be interested in

Find the area of the shape. 77 cm 8/ 12cm Please help

mestny [16]

Answer:

area of B or another side tell fast I will answer

4 0

2 years ago

-1.2 29 20 Enter the answer as an exact decimal or simplified fraction

Rudiy27

Answer:

ohh

Step-by-step explanation:

6 0

2 years ago

Which equation does this story match: The temperature is -7. Since midnight the temperature tripled and then rose 5 degrees. Wha

olya-2409 [2.1K]

5x-7=3 :))))))))))))))))))))))

4 0

2 years ago

Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

6 0

2 years ago

Gloria talked on her cell phone for 320 minutes the first mouth , and 489 minutes the third mouth . Her payment package does not

Sliva [168]

Add up minutes

1stmonth+2ndmonth+3rdmonth=320+243+489=1052
how many 200's are there
6 of them (companies want money so they see, ok, you bought like 1 minute, we will charge you for the whole 200 minutes since you got in that zone)

6 times 25=150

cost is $150 (mom is not going to be happy, she spend like 3% of her waking hours takling on the phone)

7 0

2 years ago