Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
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Answer:
9, 12
Step-by-step explanation:
Just multiply the 3,4,5 triple by 3 and u get 9, 12, 15
Answer:
6
Step-by-step explanation: You can set up the equation: = You square both sides to cancel out the squares which leaves you with = n - 4. Then you just solve as normal which ends you up with an answer of 6. You can check this by plugging 6 back into the equation and see that you end up with on both sides.
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