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Citrus2011 [14]

3 years ago

6

Isaiah is going to invest $94,000 and leave it in an account for 16 years. Assuming the interest is compounded daily, what inter

est rate, to the nearest tenth of a percent, would be required in order for Isaiah to end up with $273,000?

1 answer:

Varvara68 [4.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

r=6.7

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R = {10, 15, 20}

Umnica [9.8K]

Answer:

R n S = {20}

Step-by-step explanation:

n in sets means same elements found in the sets which are being compared

5 0

3 years ago

Find the measure of AEB<br><br> - already have answer just need the work

Digiron [165]

Based on the central angle theorem, the measure of angle AEB is: 140°.

<h3>What is the Central Angle Theorem?</h3>

According to the central angle theorem, the measure of an intercepted arc = measure of the central angle.

Arc AB = 140° [intercepted arc]

Angle AEB is the central angle.

Thus, based on the central angle theorem, the measure of angle AEB is: 140°.

Learn more about the central angle theorem on:

brainly.com/question/5436956

#SPJ1

7 0

2 years ago

What is the answer too r2+15r+36=0

Rashid [163]

R2+15r+36=0 the answer is r=6

3 0

3 years ago

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Dmitrij [34]

Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

$\frac{99}{2} (2x+98)=p^3 \\ \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}$

By substitution, we have that $p=33$ and $x=314$ .

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>

3 0

3 years ago

Set up, but do not evaluate, the integral that represents the length of the curve given by

netineya [11]

Answer:

L = ∫₀²ᵖⁱ √((1 − sin t)² + (1 − cos t)²) dt

Step-by-step explanation:

Arc length of a parametric curve is:

L = ∫ₐᵇ √((dx/dt)² + (dy/dt)²) dt

x = t + cos t, dx/dt = 1 − sin t

y = t − sin t, dy/dt = 1 − cos t

L = ∫₀²ᵖⁱ √((1 − sin t)² + (1 − cos t)²) dt

Or, if you wish to simplify:

L = ∫₀²ᵖⁱ √(1 − 2 sin t + sin²t + 1 − 2 cos t + cos²t) dt

L = ∫₀²ᵖⁱ √(3 − 2 sin t − 2 cos t) dt

7 0

3 years ago