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guapka [62]
3 years ago
6

Triangle ABC is similar to triangle LMN by the similarity postulate

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

Same as Angle B. 90 degrees.

Step-by-step explanation:

If triangles are similar then they have the exact same angle measures. Angle m will have the same value as angle B. If angle B's measure is not found, then find it by adding angle A and angle C together and subtract from 180.

The picture is cut off but if A =60 and C=30 then 60+30=90 and 180-90=90. Angle B and M are both 90 degrees.

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A set of 3 consecutive integers has a sum of 15. Which integers are they?
ludmilkaskok [199]

The answer is 4+5+6=15.Hope that helps. :)

5 0
2 years ago
Read 2 more answers
if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length
jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

7 0
3 years ago
Please help meee, I’m having trouble in math. I solved the answer but got none of these.
tino4ka555 [31]
The answer is C

2.5 + 3.4 = 5.9

So:

5.9 x 10^4
6 0
3 years ago
A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to buy the watch ? <br>​
Svetlanka [38]

Answer:

Rupees 891

Step-by-step explanation:

If you multiply 810 times 0.1 which is the decimal of 10%, you get 81 which you can add to 810 to get 891 which is the price the shopkeeper payed to buy the watch.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

7 0
2 years ago
∫c<br> x sin y ds, C is the line segment from (0, 1) to (3, 5)
Mnenie [13.5K]
Parameterize the line segment C by

\mathbf r(t)=\langle x(t),y(t)\rangle=(1-t)\langle0,1\rangle+t\langle3,5\rangle=\langle3t,1+4t\rangle

where t\in[0,1]. Then

\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt
\mathrm ds=\|\langle3,4\rangle\|\,\mathrm dt
\mathrm ds=5\,\mathrm dt

So the integral is

\displaystyle\int_Cx\sin y\,\mathrm ds=5\int_0^1x(t)\sin y(t)\,\mathrm dt
=\displaystyle5\int_0^13t\sin(1+4t)\,\mathrm dt
=\dfrac{15}{16}(\sin5-\sin-4\cos5)\approx-2.7516
3 0
3 years ago
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