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Ira Lisetskai [31]
3 years ago
12

Pls answer it very fast

Mathematics
2 answers:
dlinn [17]3 years ago
7 0
When in doubt guess c is what they say
polet [3.4K]3 years ago
3 0

Answer:

Answer is (d) 3

Step-by-step explanation:

(7/12)^-4 + (7/12)^3x = (7/12)^5

(7/12)^(-4+3x) = (7/12)^5

-4+3x = 5 [divided by 7/12 everypart]

3x =5+4

3x=9

x=9/3

x=3

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Find the general term of the sequence<br>c.1 { 10, 5, 0, -5, -10 }<br>c.2 { 1, 4, 9, 16, 25 }​
Ivan

Answer:

1. 15 - 5n where n>=1

2. n² where n>=1

Step-by-step explanation:

1. {10, 5, 0, -5, -10} is an Arithmetic Progression

nth term is a + (n - 1)d

where a = first term, n= nth term, d= common difference.

a = 10, d = -5 (5-10, 0-5, -5-0, -10-(-5))

Therefore, nth(General) term of the sequence:

= 10 + (n - 1)-5

= 10 + (-5n) + 5

= 10 + 5 - 5n

= 15 - 5n

Test:

if n = 1; 15 - 5(1) = 10

if n = 2; 15 - 5(2) = 5

if n = 3; 15 - 5(3) = 0 and so on.

2. {1, 4, 9, 16, 25}

The general term of the sequence is n²

Test:

if n = 1; 1² = 1

if n = 2; 2² = 4

if n = 3; 3² = 9 and so on.

5 0
3 years ago
Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)
givi [52]

Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

Step-by-step explanation:

Since we have given that

y=x^{8sinx}

By using logarithmic on both sides we get,

log y= 8 sinx. logx

(∵ log(a^m)=m.loga)

Now, differentiating on both sides ,we get,

\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})

\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})

\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

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3 years ago
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-by-step explanation:

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According to these three facts, which statements are true?
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