Answer:
537 students
11 days
Step-by-step explanation:
5000
y= -----------------
(1+4999e^-0.8t)
a) after 8 days means t =8
5000
y= -----------------
(1+4999e^-0.8*8)
5000
y= -----------------
(1+4999e^-6.4)
5000
y= -----------------
(1+8.306)
5000
y= -----------------
(9.306)
y =537.28
Rounding to the nearest student
y = 537 students
b) 1/2 the student population means y =2500 (The 5000 is the student population)
5000
2500= -----------------
(1+4999e^-0.8t)
Multiply each side by (1+4999e^-0.8t)
2500 (1+4999e^-0.8t) = 5000
Divide each side by 2500
(1+4999e^-0.8t) = 5000/2500
(1+4999e^-0.8t) = 2
Subtract 1
(4999e^-0.8t) = 2-1
(4999e^-0.8t)=1
Divide by 4999
(4999/4999e^-0.8t)=1/4999
e^-0.8t=1/4999
Take the natural log of each side
ln(e^-0.8t)=ln(1/4999)
-.8t = ln(1/4999)
Divide by -.8
-.8/-8t = -1/.8 *ln(1/4999)
t = -1/.8 *ln(1/4999)
t≈10.6462
Rounding, it will take 11 days
Answer:
General Formulas and Concepts:
- Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x + 1
g(x) = 3x
(f/g)(x) = f(x)/g(x)
<u>Step 2: Solve</u>
- Substitute:
Answer:
5/33649= approx 0.00015
Step-by-step explanation:
Total number of outcomes are C24 6= 24!/(24-6)!/6!=19*20*21*22*23*24/(2*3*4*5*6)= 19*14*22*23
Half of the Committee =3 persons. That mens that number of the women in Commettee=3. 3 women from 6 can be elected C6 3 ways ( outputs)=
6!/3!/3!=4*5*6*/2/3=20
So the probability that 3 members of the commettee are women is
P(women=3)= 20/(19*14*22*23)=5/(77*19*23)=5/33649=approx 0.00015
Answer:
2π/5
Step-by-step explanation:
The mean is 65 and the median is 15
