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katrin [286]
3 years ago
6

The scale on a map is 1 cm = 30 km. The map distance between two towns is 3.5 cm. What is the actual distance between the two to

wns?
Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0
The distance is 75 km
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Which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = x2 – 10x +2?
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Answer:

  • <em>The translation that maps the vertex of the graph of the function f(x) = x² onto the vertex of the function g(x) = x² - 10x + 2 is </em><u>5 units to the right and 23 units down.</u>

Explanation:

<u>1) </u><u>Vertex form</u><u> of the function that represents a parabola.</u>

The general form of a quadratic equation is Ax² + Bx + C = 0, where A ≠ 0, and B and C may be any real number. And the graph of such equation is a parabola with a minimum or maximum value at its vertex.

The vertex form of the graph of such function is: A(x - h)² + k

Where, A a a stretching factor (in the case |A| > 1) or compression  factor (in the case |A| < 1) factor.

<u>2) Find the vertex of the first function, f(x) = x²</u>

This is the parent function, for which, by simple inspection, you can tell h = 0 and k = 0, i.e. the vertex of f(x) = x² is (0,0).

<u>3) Find teh vertex of the second function, g(x) = x² -10x + 2</u>

The method is transforming the form of the function by completing squares:

  • Subtract 2 from both sides: g(x) - 2 = x² - 10x

  • Add the square of half of the coefficient of x (5² = 25) to both sides: g(x) - 2 + 25 = x² - 10x + 25

  • Simplify the left side and factor the right side: g(x) + 23 = (x - 5)²

  • Subtract 23 from both sides: g(x) = (x - 5)² - 23

That is the searched vertex form: g(x) = (x - 5)² - 23.

From that, using the rules of translation you can conclude immediately that the function f(x) was translated 5 units horizontally to the right and 23 units vertically downward.

Also, by comparison with the verex form A(x - h)² + k, you can conclude that the vertex of g(x) is (5, -23), and that means that the vertex (0,0)  was translated 5 units to the right and 23 units downward.

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3 years ago
An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What ra
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Answer:

82.62

Step-by-step explanation:

Mean score (μ) = 80

Standard deviation (σ) = 5

The 70th percentile of a normal distribution has an equivalent z-score of roughly 0.525.

For any given score, X, the z-score can be determined by:

z=\frac{X-\mu}{\sigma}

For z = 0.525:

0.525=\frac{X-80}{5}\\ X=82.62

A raw score of approximately 82.62 corresponds to the 70th percentile.

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