Answer:
v=0
Step-by-step explanation:
Answer:
= n.
Step-by-step explanation:
Given : , b is any positive number not equal to 1 and n is any number.
To find : Evaluate the expression .
Formula used : 
. = y ∙ 
(x) and
![log_{b}(b) = 1.Solution : We have [tex]log_{b} b^{n}](https://tex.z-dn.net/?f=log_%7Bb%7D%28b%29%20%3D%201.%3C%2Fp%3E%3Cp%3ESolution%20%3A%20We%20have%20%20%5Btex%5Dlog_%7Bb%7D%20b%5E%7Bn%7D)
.
By logarithm rule : . = y ∙ (x).
Then = n∙ (b).
By logarithm rule : ![log_{b}(b) = 1.Now, n∙ [tex]log_{b}](https://tex.z-dn.net/?f=log_%7Bb%7D%28b%29%20%3D%201.%3C%2Fp%3E%3Cp%3ENow%2C%20n%E2%88%99%20%5Btex%5Dlog_%7Bb%7D)
(b) = n.
Therefore, = n.
-500 is the answer, I am sure
Answer:
A: This polynomial has a degree of 2 , so the equation 12x2+5x−2=0 has two or fewer roots.
B: The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots.
Step-by-step explanation:
f(x) = 12x^2 + 5x - 2.
Since this is a quadratic equation, or a polynomial of second degree, one can easily conclude that this equation will have at most 2 roots. At most 2 roots mean that the function can have either 2 roots at maximum or less than 2 roots. Therefore, in the A category, 2nd option is the correct answer (This polynomial has a degree of 2 , so the equation 12x^2 + 5x − 2 = 0 has two or fewer roots).
To find the roots of f(x), set f(x) = 0. Therefore:
12x^2 + 5x - 2 = 0. Solving the question using the mid term breaking method shows that 12*2=24. The factors of 24 whose difference is 5 are 8 and 3. Therefore:
12x^2 + 8x - 3x - 2 = 0.
4x(3x + 2) -1(3x+2) = 0.
(4x-1)(3x+2) = 0.
4x-1 = 0 or 3x+2 = 0.
x = 1/4 or x = -2/3.
It can be seen that f(x) has two distinct real roots. Therefore, in the B category, 1st Option is the correct answer (The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots)!!!
(1,9)(-1,11)
slope = (11 - 9) / (-1 - 1) = -2/2 = -1
there can be 2 answers for this...
y - y1 = m(x - x1)
(1,9)...x1 = 1 and y1 = 9
sub
y - 9 = -(x - 1) <== here is one answer
y - y1 = m(x - x1)
(-1,11)...x1 = -1 and y1 = 11
sub
y - 11 = -(x - (-1) =
y - 11 = -(x + 1) <== here is the other answer
