The answer is; "Quadrilateral ABCD is congruent to quadrilateral A′B′C′D′ because you can map quadrilateral ABCD to quadrilateral A′B′C′D′ using a translation 7 units to the right, which is a rigid motion."
Answer: I honestly have no clue
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let x be the track straights lengths
Let y be the track ends diameter and the other rectangle side lengths.
1800 = 2x + πy
y = (1800 - 2x) / π
A = xy
A = x((1800 - 2x) / π
A = (1/π)(1800x - 2x²)
dA/dx = (1/π)(1800 - 4x)
0 = (1/π)(1800 - 4x)
0 = 1800 - 4x
4x = 1800
x = 450 m
y = (1800 - 2(450)) / π
y = 900/π or approximately 286.5 m
