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3 years ago

30 miles

Mathematics

2 answers:

zloy xaker [14]3 years ago

8 0

You said it yourself... the phrase "900 miles at 30 miles per hour" means that the fraction 900/30=30 is showing how many hours it takes to do 900 miles at a speed of 30 miles an hour. So, it took 30 hours. As with your question, I am not entirely sure of what you are asking, but from the answer choices, the most logical would be the last one, 900 miles/ ? hours. If you implement the number of hours that it takes to drive 900 miles at 30 miles per hour, the fraction would be 900 miles/ ? hours, which would then show the rate that you are driving at, 30 miles per hour.

Angelina_Jolie [31]3 years ago

7 0

Answer:

Step-by-step explanation:

because i got it right on edgenuity

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#7-9 please help with an explanation,, will mark brainliest

Mandarinka [93]

Answers:

Step-by-step explanation:

To find out which is greater, we must eliminate the radical symbol.

$\sqrt{88}$ = 9.38083151965

9.4 < 12

$-\sqrt{18}$ = -4.24264068712

-4.2 > -6

$\sqrt{220}$ = 14.8323969742

14.5 < 14.8

I'm always happy to help :)

8 0

3 years ago

Fraction is equivalent to a terminating decimal

11111nata11111 [884]

The best way to compare fractions would be to make them have like denominators. We first , in this case, need to convert from decimal to fraction.

Converting decimals to fractions first requires an understanding of the decimal places that fall after the decimal. One place after the decimal is the tenths place. If you have a decimal that ends at one place after the decimal (or in the tenths place) it can be written as the number after the decimal in the top of the fraction and ten (tenths place) in the denominator. ex. .5 ends one place after the decimal and can be written as 5/10...(read as five tenths).

If a decimal ends at two places after the decimal...(ex. .75)...it ends in the hundredths place, can be written as that number in the numerator and 100 in the denominator....(ex 75/100) and is read as seventy-five hundredths.

one place after the decimal is tenths (over 10), two places is hundredths (over 100), three places is thousandths (over 1000) , four places ten-thousandths (over 10000) and so on.

Because each decimal in your problem has a different amount of decimal places, it makes for different denominators. But, We can add a zero to the end of a decimal without changing it's value; if we add a zero to the end of .5 and make it .50 , we then can write it as 50/100 and would now have like denominators.

if .5 = .50 = 50/100 and .75 = 75/100

we now have the question what fractions can fall between 50/100 and 75/100.

That would be fractions such as 51/100, 52/100, 53/100.......74/100.

6 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)