Question

Which equation represents a line that passes through (4, 5) and has a slope of ?

Answer 1

Answer:

B

Step-by-step explanation:

To find the answer, we can use the point-slope form:

$y-y_1=m(x-x_1)$

Where (x₁, y₁) is a point and m is our slope.

Let's let our point (4, 1/3) be (x₁, y₁) respectively.

We also know that our slope is 3/4. So, substitute 3/4 for m.

This yields:

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

The choice that represents this is B.

So, our correct answer is B.

And we're done!

Answer 2

Answer:

$y - \frac{1}{3} = \frac{3}{4} (x - 4)$

Step-by-step explanation:

Given the line passes through (4, 1/3) and it's slope is 3/4

$y = mx + c$

$slope = m$

$m = \frac{3}{4}$

$y = \frac{3}{4} x + c$

At (4, 1/3)

$\frac{1}{3} = \frac{3}{4} (4) + c$

$c = - \frac{8}{3}$

$y - intercept = - \frac{8}{3}$

The equation of the line:

$y = \frac{3}{4} x - \frac{8}{3}$

The answer is:

$y - \frac{1}{3} = \frac{3}{4} (x - 4)$

*if you expand the equation above you will get the equation of line you initially got*