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2 years ago

Can somebody help me with these problems please

Mathematics

1 answer:

mario62 [17]2 years ago

3 0

Answer:

11. A. $\frac{12}{13}$

12. D. $\frac{35}{12}$

Step-by-step explanation:

11: Sin is just the side opposite of the angle divided by the hypotenuse of the triangle

Opposite of A = 36

Hypotenuse of the triangle = 39

36/39 = $\frac{12}{13}$

12. Tan is the side opposite of the angle divided by the side adjacent to the angle

Opposite of C = 35

Adjacent to C = 12

35/12 = $\frac{35}{12}$

Hope this helps!

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Help meh I will give brainiest!! Answer as much as you know.

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Unit 7 Review Guided Notes Page

Question 1

Find the missing side length.

5*5=25+ 7*7=49= 74 so 8.6

Question 2

What is the area of the parallelogram?

18*50=900

Question 3

What is the perimeter of the figure?

If you break the object apart. 7+7+1+1=16

5+5+3+3=16

16+16=32m

Question 4

What are the solutions to the equation?

x^2 – 22 = 14

I found that 6*6=36 – 22=14

I tried a few numbers .

Question 5

What is the area of the figure?

If you break the figure apart. 3*2=6

2*6=12

6+12=18cm

Question 6

What is the area of the trapezoid?

11+3=14*9=126*2=252

Question 7

Hint: 1 Revolution equals the Circumference!

How far does a wheel travel in 2 revolutions if it has a radius of 45 cm?

2*3.14=6.28*45=282.6*2=565.2

Question 8

The diameter of the larger circle is 11 cm. The diameter of the smaller circle is 7 cm. What is the area approximate area of the shaded region?

For the smaller one – 7/2= 3.5 *3.5*3.14=38.46

For the bigger one- 5.5*5.5*3.14=94.98

94.98-38.46=56.52

Question 9

What is the approximate area of a circular garden that has a diameter of 12 feet?

A= Pi*r2. 3.14*6^2 =113

6*6=36*3.14= 113.04

Question 10

A 17-foot pole is leaning against a wall. The bottom of the pole is 8 feet away from the bottom of the wall. Approximately how high up the wall does the top of the pole reach?

(a^2+b^2=c^2) Its 15 ft

4 0

3 years ago

From a point on the ground 12 ft. from the base of a flagpole, the angle of elevation of the top of the pole measures 53°. How t

torisob [31]

Answer:

4.75 feet

Step-by-step explanation:

Let the height of the flagpole be x

Sin 53 = x/12

x = 12 × Sin 53

x = 12 × 0.3959

x = 4.75 feet

5 0

3 years ago

The point (5, -2) is rotated 90° about the origin. Its image is:

Morgarella [4.7K]

Image below, rotation for point (5,-2) gives you (2,5).

8 0

3 years ago

Which equation can be solved to find one of the missing side lengths in the triangle?aB60512 unitsАCOS(60°) =22 믕cos(60°) = 12Su

Mekhanik [1.2K]

In a right rectangle, we have:

$\sin \alpha=\frac{opposite}{hypotenuse}$ $\cos \alpha=\frac{\text{adjacent}}{hypotenuse}$

For your exercice, hypotenuse=12

The exercise also inform the angle 60°, then:

$\sin \text{ 60}=\frac{\text{opposite}}{\text{hypotenuse}}=\frac{b}{12}$ $\cos 60=\frac{adjacent}{\text{hypotenuse}}=\frac{a}{12}$

3 0

1 year ago

(3p+5)(2) simplified

Vsevolod [243]

Multiply each term in the parentheses by 2
3p x 2 +5 x2

Calculate the product
6p+5 x 2

Multiple the number
6p x 10

That’s your answer
6p x 10

8 0

2 years ago