The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer: 1.5
Step-by-step explanation: Reverse the equation to get the answer.
-13 divided by 2 is -6.5
add 8 and you'll get 1.5
1 clipe..............7/8
x.......................56
7x/8 = 56
7x = 56*8
x = 56*8/7
x = 8*8
x = 64 clipes
1 clipe = 0,03
64 clipes = 0,03*64
64 clipes = 1,92
Answer:
0 real # solution
Step-by-step explanation:
b^2-4ac<1 is equal to 0 real number solution and
-5(2+1)=-22+10
-5(2+1)=-12
which is less than 1
Answer:
Please make it a bit bigger.
Step-by-step explanation:
I can't see it
