Interval notation
(-infinity sign, 1)
Set-builder notation
{x|x less than equal to 1}
Only problem is with the simplifying.
We all know that 5/5 = 1, it is natural to assume (x+a)/(x+a) is also 1, but in some cases where x+a=0, it is undefined. In this equation, where they simplify (x-2) and (x-6), you must say that x is not 2 nor 6 or, you just delete 0/0 which is undefined.
Therefore the only solution would be x=-1
The equation would be 3l-5.
Answer:
166
Step-by-step explanation:
A=2(wl+hl+hw)=2·(4·5+7·5+7·4)=166
A + R + J = 1925
A = 1/2R
J = 2R
1/2R + R + 2R = 1925
7/2R = 1925
R = 550
J = 2(550)
J = 1100
Joel collects 1100 cans.