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77julia77 [94]
3 years ago
10

A customer states that when she removes the printed pages from her laser printer output tray, the black ink smears all over her

fingers. Which of the following is the most likely problem?
A. Inked ribbon
B. Fuser unit
C. Primary corona
D. Cleaning blade
E. Erasure lamps
Computers and Technology
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

B. Fuser unit

Explanation:

Based on the scenario that is being described it can be said that the most likely problem is the Fuser unit. This is a part that plays an important role in the printing process. This unit melts the toner and compresses it in order to leave the impression on the paper with heat. A faulty fuser unit will not compress correctly and leave wet ink on the paper causing it to smear.

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What is the formula equivalent to the function =SUM(B1:B5)? A. =B1+B5 B. =$B$1+$B$5 C. =B1+B2+B3+B4+B5 D. =$B$1+$B$2+$B$3+$B$4+$
Contact [7]

Given the options, I would choose Option C. =B1+B2+B3+B4+B5.

5 0
3 years ago
Ted has $55.00 in his pocket. Which purchase will he be able to pay for with cash?
Alex73 [517]
You just need a little bit of math to solve this. Add up the items and see which one would be equal to $55.00 or less. 

A = $59.90 so this is not the answer
B = $60.94 so this is not the answer
C = $55.99 so this is not the answer

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D is the correct answer.
3 0
3 years ago
Read 2 more answers
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

8 0
3 years ago
Differentiate between system software and application software
vodomira [7]

Answer:

system software is the software which control overall operation of the computer . For eg. Ms.dos ,window 2003 ,etc whereas application software is a software which work on the top of operating system to solve number of problems .For eg. Ms.word,Ms.excel,etc

3 0
3 years ago
Read 2 more answers
Formulas should follow the___
tatuchka [14]

Answer:

Order of operations

Explanation:

4 0
3 years ago
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