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Lapatulllka [165]
3 years ago
6

What important information is needed if you are installing an oem version of windows 7?

Computers and Technology
1 answer:
Kipish [7]3 years ago
3 0
I think you would need the OEM license 
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Given the following adjacency matrix, what is the approximate rank vector after one iteration of the power iteration method (use
ValentinkaMS [17]

Note: The matrix referred to in the question is: M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

Answer:

a) [5/18, 5/18, 4/9]'

Explanation:

The adjacency matrix is  M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

To start the power iteration, let us start with an initial non zero approximation,

X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]

To get the rank vector for the first Iteration:

X_1 = MX_0

X_1 =  \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\

Multiplying the above matrix by 1/3

X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]

8 0
3 years ago
Please help me with Excel!!! A lot of points!
yaroslaw [1]

Answer:

=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE))/12

Explanation:

Adds all of the Monthly Expenses : SUM(PUT RANGE OF MOTHLY EXPENSES HERE)

Multiplies the result by 12: *12

Then adds all of the Yearly Expenses to the product of Steps 1 and 2 : SUM(PUT RANGE OF YEARLY EXPENSES HERE)

Divides this new sum by 12: /12

=((SUM(PUT RANGE OF MOTHLY EXPENSES HERE)*12)+SUM(PUT RANGE OF YEARLY EXPENSES HERE)/12)

6 0
3 years ago
The second stage of digestion takes place in the small intestine. <br> True Or False?
DedPeter [7]
False. The second stage of digestion happens in the stomach.
8 0
3 years ago
Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s
schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

Area = 0.5 * b * h

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

s = \sqrt{b^2 + h^2}

The perimeter of the triangle is then calculated as thus;

Perimeter = s + s + b

Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b

Perimeter = 2\sqrt{b^2 + h^2} + b

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

Volume = \frac{1}{3} \pi * r^2 * h

Where r = \frac{1}{2} * diameter

So, r = \frac{1}{2}b

So, Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

 

return 0;

}

3 0
3 years ago
Recall that the name of a transport-layer packet is segment and that the name of a link-layer packet is frame. What is the name
AlladinOne [14]

Answer:

A network-layer packet is a data gram. A router forwards a packet based on the packet's IP (layer 3) address. A link-layer switch forwards a packet based on the packet's MAC (layer 2) address.

Explanation:

When the end system receives the unstructured bit stream from the physical wire, each layer removes the header information applicable to it until the application receives the data.

1. An application, such as an email program, creates data that will be sent by an end user, such as an email message. The Application layer places a header (encapsulation) field that contains information such as screen size and fonts, and passes the data to the Presentation layer.

2. The Presentation layer places layer 6 header information. For example, the text in the message might be converted to ASCII. The Presentation layer will then pass the new data to the Session layer (layer 5).

3. The Session layer follows the same process by adding layer 5 header information, such as information that the Session layer will manage the data flow, and passes this data to the Transport layer (layer 4).

4. The Transport layer places layer 4 information, such as an acknowledgement that the segment was received in the header, and passes it to the Network layer (layer 3).

5. The Network layer places layer 3 header information, such as the source and destination address so the Network layer can determine the best delivery path for the packets, and passes this data to the Data Link layer (layer 2).

6. The Data Link layer places layer 2 header and trailer information, such as a Frame Check Sequence (FCS) to ensure that the information is not corrupt, and passes this new data to the Physical layer (layer 1) for transmission across the media.

7. The bit stream is then transmitted as ones and zeros on the Physical layer. It is at this point that the Physical layer ensures bit synchronisation. Bit synchronisation will ensure the end user data is assembled in the correct order it was sent.

8. Steps 1 through 7 occur in reverse order on the destination device. Device B collects the raw bits from the physical wire and passes them up the

Data Link layer. The Data Link layer removes the headers and trailers and passes the remaining information to the Network layer and so forth until data is received by the Application layer. Eventually, Device B will receive an email notification displaying a message to indicate that a new email message has been received.

5 0
3 years ago
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