Least- 2
Greatest- 12
Median- 7
Lower Q- 4
Upper Q- 8
Range-10
IQR- 4
This is pretty simple. All you have to do is make the first and second fraction share a denominator by multiplying them by each other.
6 <span>• 9 = 54
Then multiply each numerator by the opposing denominator.
1 </span><span>• 9 = 9
2 </span><span>• 6 = 12
Here are the new fractions:
9/54
12/54
Now add the 9 and 12 together.
9 + 12 = 21
The complete fraction:
21/54
Subtract 21 from 54 so you can get the remainder of the sweater.
54 - 21 = 33
This is the remainder fraction:
33/54
Can you simplify this? Yes, of course! They can both be divided by 3!
11/18
That is the remainder of the sweater. But you still have to divide it in half! After all, Linda only knitted half of the remaining sweater. Dividing it in half can be done just by multiplying the denominator by 2.
11/36
That should be your answer! Apologies if I got something wrong.</span>
Your formula for this is
and
. Get everything on one side of the equals sign, set it equal to 0 and factor. When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27. The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
Answer:
a) 29
b) 0
c) 7
d) 3/8
Step-by-step explanation:
Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.
If the result is negative, you add the clock hours.
a) 21 - 33 = -12 , so -12 + 41 = 29
b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.
c) 11+19 = 30, 30 - 23 = 7
d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.
