Answer:
Step-by-step explanation:
Answer:
The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.
Step-by-step explanation:
To solve this question, we use the central limit theorem.
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , the sample means with size n can be approximated to a normal distribution with mean and standard deviation
In this problem, we have that:
The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.
Answer:
Step-by-step explanation:
1. Not
2. Yes
3. not
Answer:
4
Step-by-step explanation:
Given the data:
X : 20,25,30,20,30
Mean absolute deviation :
Σ(x - xbar) / n
n = sample size = 5
xbar = ΣX / n = (20+25+30+20+30) /5
xbar = 25
((20-25) + (25-25) + (30-25) + (20-25) + (30-25)) / 5
We take the absolute values, hence, negative signs are ignored :
(5 + 0 + 5 + 5 + 5) / 5
20 / 5
= 4