The midpoint of the line having the endpoints
and
is
basically average them
so given that the line has the endpoints of (-3,7) and (9,-2)
x₁=-3
y₁=7
x₂=9
y₂=-2
so the midpoint can be found by doing
the midpoint is
Answer:
All real numbers are solutions
Step-by-step explanation:
Let's solve your equation step-by-step
3(x+2)=5x+1−2x+5
Step 1: Simplify both sides of the equation
3(x+2)=5x+1−2x+5
(3)(x)+(3)(2)=5x+1+−2x+5(Distribute)
3x+6=5x+1+−2x+5
3x+6=(5x+−2x)+(1+5)(Combine Like Terms)
3x+6=3x+6
3x+6=3x+6
Step 2: Subtract 3x from both sides
3x+6−3x=3x+6−3x
6=6
Step 3: Subtract 6 from both sides
6−6=6−6
0=0
5:4 Should be correct! I took the test Btw Hope this helps!! :D
Given equation is y=2x+7 and 
Let's simplify the 2nd equation before we can start graph so that calculation will be easy
multiply both sides by 2 to cancel out fractions
y=2x+7
which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.
y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.
Answer:
<h3>
BC = 29</h3>
Step-by-step explanation:
Point B is between A and C and the points A, B, and C are collinear so:
AB + BC = AC
487 + 5x + 8x + 709 = 91
13x + 1196 = 91
- 1196 - 1196
13x = - 1105
÷13 ÷13
x = - 85
BC = 8x + 709 = 8(-85) + 709 = - 680 + 709 = 29
