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marysya [2.9K]
3 years ago
10

A 10​-ft vertical post casts a 12​-in shadow at the same time a nearby cell phone tower casts a 126​-ft shadow. How tall is the

cell phone​ tower?
Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0

The cell phone tower is 1260 feet tall

<em><u>Solution:</u></em>

Given that 10​-ft vertical post casts a 12​-in shadow

At the same time a nearby cell phone tower casts a 126​-ft shadow

To find: height of cellphone tower

We can use proportion to solve the sum

\frac{\text {height of post }}{\text {shadow of post}}=\frac{\text {height of tower}}{\text {shadow of tower}}

Here,

Let "x" be the height of tower

height of post = 10 feet

shadow of tower = 126 feet

shadow of post = 12 inches

We know that,

1 inches = 0.0833333 foot

12 inches = 12 x 0.0833333 foot = 1 foot

shadow of post = 1 foot

Thus the proportion becomes,

\frac{10}{1} = \frac{x}{126}

10 \times 126 = x \times 1\\\\x = 10 \times 126 = 1260

Thus the cell phone tower is 1260 feet tall

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A. The length of the second leg is 8.5 inches

B. The length of the three-dimensional diagonal is 9.9 inches

Step-by-step explanation:

Let us revise the relation between the hypotenuse and the two legs of a right triangle

(hypotenuse)² = (vertical leg)² + (horizontal leg)²

∵ The length of the rectangular box = 8 inches

∵ The width of the rectangular box = 3 inches

∵ The height of the rectangular box = 5 inches

∵ Length and width are perpendicular to each other

∴ The Δ whose legs are 3 and 8 is a right triangle

In the right Δ whose legs are 3 and 8

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A.

The 3-dimensional diagonal is the hypotenuse of a right triangle whose legs are the vertical edge and the hypotenuse of the right triangle whose legs are 3 and 8

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B.

In the right triangle whose hypotenuse is the 3-dimensional diagonal and legs are the vertical edge , the hypotenuse of the right triangle whose legs are 3 and 8

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∴ 3-dimensional diagonal = \sqrt{98} = 9.899494937

- Round it to the nearest tenth of an inch

∴ 3-dimensional diagonal = 9.9 inches

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