3 years ago

Find an equation of the line parallel to y= 1/3x +1 and that passes through the point (3,5)

1 answer:

6 0

So in order to find the line you’ll have to submit the point (3,5) and the slope into the point slope formula : y-y1= m(x-x1)

Y-5= 1/3(x-3)

Solve(turn to y intercept form):

Y-5= 1/3x -1

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Illusion [34]

The first option is greater.

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Dmitrij [34]

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F(x) = | 3x +4 |+2<br> g(x)=4<br> Find (f +g)(x)

iVinArrow [24]

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Step-by-step explanation:

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3 years ago

Given line t passes through (0,-5) and (-1,3) and liner passes through (-4,3) and (4,2).

kupik [55]

Answer:

neither

Step-by-step explanation:

Slope of the first line: (y2 -y1)/(x2-x1) = (3-(-5)/-1 = 8/-1 = -8

Slope of the second line: (2-3)/4-(-4) = -1/8

They are neither parallel nor perpendicular. In fact the two lines have different slope so they can’t be parallel. In addition the product of their slope is not -1, so they can’t be perpendicular,

3 0

3 years ago

I need to solve for x - 6(2x-5)=-(x+4)

sdas [7]

Distribute
x-12x+30=-x-4

Combine like terms
-11x+30=-x-4

Add x to both sides
-10x+30= -4

Subtract 30 from both sides
-10x=-34

Divide both sides by -10
x=3.4

Final answer: x=3.4

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