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Goryan [66]
3 years ago
6

Find an equation of the line parallel to y= 1/3x +1 and that passes through the point (3,5)

Mathematics
1 answer:
bulgar [2K]3 years ago
6 0
So in order to find the line you’ll have to submit the point (3,5) and the slope into the point slope formula : y-y1= m(x-x1)

Y-5= 1/3(x-3)

Solve(turn to y intercept form):

Y-5= 1/3x -1



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Michael is a real estate agent who sells a house. He received $5,250 for a 3% commission on the house. How much did the house se
Alborosie

Answer: $157.50

Step-by-step explanation:

$5250÷100=$52.50

52.50×3=$157.50

7 0
3 years ago
Read 2 more answers
if there are 12 dogs that sell for $104 and 8 cats that sell for $25. At the end of the day there are 4 dogs left and 5 cats lef
Vinil7 [7]

Initially there were 12 dogs

dogs left at the end of day =4

number of dogs sold=12-4=8

price of one dog=$104

price of 8 dogs = 104*8= $832

initially there were 8 cats

cats left at the end of day =5

number of cats sold =8-5=3

price of one cat= $25

price of 3 cats =25*3= $75

ratio of sales for dogs to cats = 832/75

7 0
3 years ago
ALOT OF POINTS IF YOU HELP ME PLEASE EXPLAIN ​
Svetllana [295]

Answer:

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).

Step-by-step explanation:

Misha's group was asked to write an expression equivalent to  

7y²z + 3yz² - 3

When Mr. Chen checked their answers, he found only one to be correct.

And she was Helena.

Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).  

Because, (7y²z + 6yz²- 5 - 3yz² + 2)

= 7y²z + (6yz² - 3yz²) - (5 - 2)  

= 7y²z + 3yz² - 3 (Answer)

4 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
What is 3-2y+(-8y)+8.4 as a simplified expression
IRISSAK [1]

Answer:

-10y + 11.4

I hope this helps you out

7 0
3 years ago
Read 2 more answers
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