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3 years ago

Find the volume of the solid to the nearest unit.

Mathematics

1 answer:

Eva8 [605]3 years ago

8 0

Volume of the bottom cuboid = 5 x 6 x 3 = 90 ft³

Volume of the pyramid = 1/3 x 5 x 6 x 3 = 30 ft³

Total = 90 + 30 = 120 ft³

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The expression sin x (cos x cot x - sin x) simplifies to?

nikdorinn [45]

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3 years ago

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Jamie made 8 1/4 cups of fruit punch for a party. Her guests drank 2/3 of the punch. How many fruit punch did her guests drink?

garri49 [273]

The answer would be 7 7/12

7 0

2 years ago

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alexdok [17]

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3 years ago

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Sqaure root of 5 (u-1)(u^5+u^4+u^3+u^2+u+1)

Anna71 [15]

GIVEN:

$5(u - 1)( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1)$

remember:

$\sqrt{u} = {u}^{ \frac{1}{2} }$

And

${u}^{n} \times {u}^{m} = {u}^{n + m}$

SOLVE:

start by multiplying the factors:

$5( ({u}^{6} + {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u ) - ( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1))$

simplify by combing like terms. Most terms subtract off, leaving:

$5( {u}^{6} - 1)$

This can be factored, but it is not a perfect square, which is really what we need to take the square root.

$5( {u}^{3} - 1)( {u}^{3} + 1)$

I'm not exactly sure what form they want the answer in...

so taking the square root:

$\sqrt{5( {u}^{6} - 1) } = {(5( {u}^{6} - 1))}^{ \frac{1}{2} }$

so my best answer is:

${5}^{ \frac{1}{2} } \times {( {u}^{6} - 1)}^{ \frac{1}{2} }$
or the more factored form:

${5}^{ \frac{1}{2} } { ({u}^{3} - 1)}^{ \frac{1}{2} } { ({u}^{3} + 1 )}^{ \frac{1}{2} }$

I'm not sure how else to solve it. Taking the square root doesn't work out super well, so I left it in the most simple form I could.

sorry for not coming to a definitive answer!

7 0

3 years ago

Six thousand,six hundred forty_one dollars and forty cent in standard form

iVinArrow [24]

The answer is: 6,641.40$

Explanation:

Six thousand= 6,000

Six hundred= 600

Forty one= 41

Forty cents: .40

Now add all of these together:

6,000

+ 600

+ 41

+ 0.40

Which will give you 6,641.40$

I hope this helps! :)

-LizzyIsTheQueen

4 0

2 years ago