The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
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Answer: it means to make larger or smaller.
Step-by-step explanation:
it means to make larger or smaller.
Answer:
Convergent; 81
Step-by-step explanation:
r = term2/term1 = 8/9
8/9 < 1 so convergent
Sum = 9/(1 - 8/9)
= 9/(1/9) = 81
You use the formula C=2(3.14)r r is the radius and in this situation 2 so the answer will be 12.56
