Answer:
Step-by-step explanation:
For the disease having force of mortality µ.
we apply exponential distribution law
probability of dying within 20 years
p( x <20) = 
= .1
= .9
For the disease having force of mortality 2µ.
we apply exponential distribution law
probability of dying within 20 years
p( x <20) = 1 - 
= 1 - ( .9)²
= 1 - .81
= .19
or 19%
Answer:
The answer is 33 years.
Step-by-step explanation:
10% of 3 is .3
Just move the decimal to the left.
.3 times 33=9.9
9.9~10
We know that
Based on the table
Percent%=[1-Decay factor]*100%
so
for decay factor=0.98
Percent%=[1-0.98]*100%----> 2%
for decay factor=0.50
Percent%=[1-0.50]*100%---->50 %
for decay factor=0.64
Percent%=[1-0.64]*100%----> 36%
for decay factor=0.23
Percent%=[1-0.23]*100%----> 77%
therefore
the answer is
36%
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
Answer:
44
Step-by-step explanation:
56 - 12= 44
