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kotegsom [21]
4 years ago
7

(-2)^-3 without exponent

Mathematics
2 answers:
miss Akunina [59]4 years ago
8 0

Answer:

-1/8

Step-by-step explanation:

\left(-2\right)^{-3}\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\\left(-2\right)^{-3}=\frac{1}{\left(-2\right)^3}\\\\=\frac{1}{\left(-2\right)^3}\\\\\left(-2\right)^3=-8\\\\=\frac{1}{-8}\\\\=-\frac{1}{8} \\\\\left(\mathrm{Decimal:\quad }\:-0.125\right)

Basile [38]4 years ago
7 0

Answer:

-1/8

Step-by-step explanation:

(-2)^-3 \\=\frac{-1}{2}^{3}\\=\frac{-1}{8}

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