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Whitepunk [10]
3 years ago
14

At the beginning of football season, Coach Carnes takes inventory of the team equipment to see what he needs. He counts 24 footb

alls, but he needs to start off the season with at least 75. The footballs that he uses are sold in packages of 4. How many packages could the coach buy?
Mathematics
1 answer:
Leviafan [203]3 years ago
6 0

Answer:

13

Step-by-step explanation:

To solve this, lets first find the number of footballs he still needs:

75-24 = 51

Now to find the number of packages, divide by 4, since there are 4 balls per package:

51/4 = 12 Remainder 3

Since there is a remainder, and the Coach MUST have at least 75, then we need to add a package to include the remainder:

12 + 1 = 13 Packages

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Triangle ABC is an equilateral triangle. Segment AD measures 18 inches.Which statements about the diagram are correct? Check all
Margaret [11]

Answer:

The correct answer is option C and D.

C). DC = 6√3

D). AC = 12√3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control
lianna [129]

Answer:

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

Step-by-step explanation:

There are a total of <em>N</em> = 25 aluminum castings.

Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of samples that are possible as follows:

{25\choose 3}=\frac{25!}{3!\times (25-3)!}

      =\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

6 0
3 years ago
Calculate the value of A in the statement​
tigry1 [53]

please edit your question man

4 0
2 years ago
Factorise 24e^2-28e-12
Helga [31]

Answer:

4(2e - 3)(3e + 1)

Step-by-step explanation:

Given

24e² - 28e - 12 ← factor out 4 from each term

= 4(6e² - 7e - 3) ← factor the quadratic

Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.

product = 6 × - 3 = - 18 and sum = - 7

The factors are - 9 and + 2

Use these factors to split the e- term

6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )

= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term

= (2e - 3)(3e + 1)

Then

24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form

8 0
3 years ago
Can some one help me with 1,3,and 5
FrozenT [24]

1. 2/100 or 1/50, as 0.02 is equal to 2 hundreths. Simplifying gets you 1/50

3. 1/2 or 50/100, as 0.50 is equal to 0.5 which is equal to 50 hundreths. Simplify to get 1/2

5. 88/100 or 44/50 , as 0.88 is equal to 88 hundreths. After simplifying, you get 44/50

Depending on your teacher, you may be told to not simplify. It depends

8 0
3 years ago
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