Evaluate Tan ^-1 (-1). Enter your answer in radians.<br> Answer here

How do you solve 36 times <img src="https://tex.z-dn.net/?f=%5Csqrt%7B3%7D" id="TexFormula1" title="\sqrt{3}" alt="\sqrt{3}" ali

pantera1 [17]

Answer:

62.3538

Step-by-step explanation:

There is nothing to solve. If you need a decimal value, you can use a calculator or table of square roots.

8 0

3 years ago

Find the equation of a line parallel to x+y=8 that passes through the point (-8,-2)

notsponge [240]

Answer
The last one
y+2=-(x+8)

6 0

2 years ago

A poll was conducted by a home mortgage company regarding home ownership in the United States. The company polled 1,488 American

____ [38]

If the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

Given sample size of 1488, percentage of those polled own a home be 69% and confidence level be 99%.

We are required to find the approximate margin of error.

Margin of error is the difference between calculated values and real values.

n=1488

p=0.69

Margin of error=z* $\sqrt{p(1-p)/n}$

Z score when confidence level is 99%=2.576.

Margin of error=2.576* $\sqrt{0.69(1-0.69)/1488}$

=2.576* $\sqrt{(0.69*0.31)/1488}$

=2.576* $\sqrt{0.2139/1488}$

=2.576* $\sqrt{0.0001437}$

=2.576*0.01198

=0.03088

Hence if the sample size is 1488 and confidence interval of 99% then the margin of error is 0.03088.

Learn more about margin of error at brainly.com/question/10218601

#SPJ1

3 0

1 year ago

Find a function where f(0)=2 and f(1)=2

xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

$f(x) = x^2-x+2$

Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need $A= 2$ , and at that point the first condition is guaranteed; using the second to find k we get $2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi$