19.2
To find the hypotenuse the equation would be: a^2 + b^2 = c^2.
12 squared is 144 and 15 squared is 225. Add them and you get 369. Then, square root 369 to isolate c. It'd be about 19.2
Obviously, what you looking for is slopes. Now let's get started.
6.) 7x-5y=20 You subtract 7x both sides.
-7x -7x
-5y=-7x+20 Then you divide -5 both sides (which is include -7 and 20).
y=7/5x-4 Simplify.
-8x-3y=12 Add 8x both sides because it's a negative number.
+8x +8x
-3y=8x+12 Divide -3 both sides.
y=-8/3x-4 Simplify.
And your point value is (0,-4).
7.) -x-4y=12 Add x both sides.
+x +x
-4y=x+12 Divide -4 both sides.
y=-1/4x-3 Simplify.
20x+80y=0 Subtract 20x both sides.
-20x -20x
80y=-20x Divide 80 both sides. Here's a hint: 20/80 is same thing as 2/8, so
you don't have to do all that.
y=1/4x Simplify. Here's another hint: I bet you wondering there's no y- intercept. The y-intercept is (0,0).
Both of the functions are parallel, so there's no solution.
8.) 30x+50y-100=0 Add 100 both sides.
+100 +100
30x+50y=100 Subtract 30x both sides.
-30x -30x
50y=-30x+100 Divide 50 both sides.
y=-3/5x+2 Simplify.
3x-15y-30=0 Add 30 both sides.
+30 +30
3x-15y=30 Subtract 3x both sides.
-3x -3x
-15y=-3x+30 Divide -15 both sides.
y=1/5x-2 Simplify.
And your point value is (5,-1).
I hope it helps.
Answer:
Q1: 
Q2: 
Step-by-step explanation:
The derivative of the product of two functions is:
The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.
Q1: The function you are given is:
You can think of that function as the product of functions
and 
We first find the derivatives of functions u and v:
and 
Now we follow the rule above:
Use the commutative property to change the order of the sum.
This is the solution you have.
Q2: The function you are given is:
You can think of that function as the product of functions
and 
We first find the derivatives of functions u and v:
and 
Now we follow the rule above:
Answer:
simple quadrilateral with two pairs of parallel sides. The opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure
Step-by-step explanation:
Answer:
No.
Step-by-step explanation:
If we combine all like terms first on the left, then the right-
We will have a solution of
-8+12b=12b-14
This is not true, therefore, 8b−10+b+3b+2=7+2b+10b−18−3 does not have a solution.
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