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Elanso [62]
4 years ago
7

I need help with 14, 15 and 16 plz ​

Mathematics
1 answer:
Natalka [10]4 years ago
5 0
14. Is 25 percent
15. 20 percent
16.
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Complete each statement with a number that makes the statement true. Value of x that would make the statement on the left true
melomori [17]

Step-by-step explanation:

D. x>-2°C =

8 0
3 years ago
What Is the solve for n of 2 (8 + 3n) < 34
GREYUIT [131]

Answer:

n<3

Step-by-step explanation:

2(8 +3n) < 34

16 + 6n < 34

6n < 34-16

6n < 18

n < 3

8 0
4 years ago
The distributive property combines (blank) and (blank) to make multiplying whole numbers simpler.
emmasim [6.3K]
I am not too sure whether there were options, but one way to approach this is to fill it with "multiplication" and "addition" - the distributive property combines addition and multiplication to make multiplying whole numbers simpler. The gain is that you don't have to make one difficult multiplication, but a couple of simpler ones and then you can add them up.
4 0
4 years ago
Four brothers have ages which are consecutive even integers. If the product of the ages of the two middle brothers is 528, how o
exis [7]

Answer:

The oldest brother is of age 26 years.

Step-by-step explanation:

As the age of four brothers are consecutive even integers.

We assume that the ages are x,(x+2),(x+4),(x+6) as their respective ages.

And the age of the youngest brother x yrs.

Age of the oldest brother (x+6) yrs.

According to the question

Product of two middle brother that is (x+2)(x+4) =528

So we will arrange this in our equation and solve the quadratic.

(x+2)(x+4) =528

x^{2}+4(x)+2(x)+8 =528

x^{2}+4(x)+2(x)+8-528=0

x^{2}+6(x)-520=0

Solving the quadratic by using middle term splitting or directly with quadratic formula we can find the value of 'x' .

Here it is solved with quadratic formula:

Comparing with standard equation ax^{2}+b(x)+c=0,here a=1,b=6\ and\ c=-520.

x= \frac{-b \pm \sqrt{b^2-4ac} }{2a} = \frac{-6 \pm \sqrt{6^2-4\times \ (-520)} }{2\times 1}

x=20,-26

We will work with the positive value of (x) so the the age of the youngest brother =(x)=20 yrs.

And the age of the the oldest brother =(x+6)=(20+6)=26 years.

The age difference is of (26-20)=6 years.

4 0
4 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
fomenos

Answer:

Advance tickets=$25

Same-day tickets=$15

Step-by-step explanation:

Complete question below:

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?

Let

advance tickets=x

Same-day tickets=y

Combined cost of advance and same-day tickets=$40

It means,

x+y=40 Equ (1)

25 advance tickets and 30 same-day tickets=$1075

It means,

25x+30y=1075 Equ(2)

From (1)

x+y=40

x=40-y

Substitute x=40-y into (2)

25x+30y=1075

25(40-y)+30y=1075

1000-25y+30y=1075

5y=1075-1000

5y=75

Divide both sides by 5

5y/5=75/5

y=15

Recall,

x+y=40

x+15=40

x=40-15

=25

x=25

Advance tickets=$25

Same-day tickets=$15

Check

25x+30y=1075

25(25)+30(15)=1075

625+450=1075

1075=1075

3 0
4 years ago
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