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beks73 [17]
3 years ago
15

Write an equation for the line through (2,2), y-intercept 10

Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0
Y = -5x + 10
Your welcome for the help!
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Robert is 10 years older than her brother. In 2 years, Robert will be three times as old as his brother. How old are they now?
valentina_108 [34]
Robert is 13 and his brother is 3 y.o.
X... brother’s age
X+10... Robert’s age
X+10+2... Robert’s age in 2 years
X+2...Brother’s age in 2 years
X+10+2/x+2=3
X=3
X+10=13
6 0
3 years ago
What feature of the box and whisker plot does the IQR describe
Oksanka [162]
The IQR tells you how spread out the "middle" values are. It can also be used to figure out if there are any outliers.
5 0
3 years ago
1)The computer accessory that Joanne is considering
ankoles [38]

Answer:

Check Explanation.

Step-by-step explanation:

- A sample space includes all the possible outcomes of a statistical event. It refers to all the possible results, values that a statistical event can take on.

- Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

a) Joanne is considering selling a computer accessory at her store and the accessories come in white, beige, gray or black and as an optical mouse, mechanical mouse or trackball.

This means that an accessory can be white and an optical mouse, white and a mechanical mouse or white and a trackball.

This can be done for the 3 other colours.

So, the sample space for the accessory spans:

(white, optical mouse), (white, mechanical mouse), (white, trackball), (beige, optical mouse), (beige, mechanical mouse), (beige, trackball), (gray, optical mouse), (gray, mechanical mouse), (gray, trackball), (black, optical mouse), (black, mechanical mouse), (black, trackball)

The probability that someone gets beige and a mechanical mouse

Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

Number of outcomes with an accessory that is beige and a mechanical mouse = 1

Number of events in the sample space = 12

The probability that someone gets beige and a mechanical mouse = (1/12) = 0.0833

b) Jackie has three pairs of jeans: Joe Brand, Levis and Seven. She also has 4 tops: red, blue, purple and pink.

The sample space for Jackie's outfits is;

(Joe Brand, red), (Joe Brand, blue), (Joe Brand, purple), (Joe Brand, pink), (Levis, red), (Levis, blue), (Levis, purple), (Levis, pink), (Seven, red), (Seven, blue), (Seven, purple), (Seven, pink)

The chance she wears the Joe Brand or Levis and a purple top.

Number of outcomes with an outfit of Joe Brand or Levis and a purple top = 2

number of outfits on the sample space = 12

The chance she wears the Joe Brand or Levis and a purple top = (1/6) = 0.1667

c) A surfer owns 5 wetsuits: brown, black, pants, shorts and green. He also owns 3 surf boards: blue, green and red.

Sample space includes

(brown, blue), (brown, green), (brown, red), (black, blue), (black, green), (black, red), (pants, blue), (pants, green), (pants, red), (shorts, blue), (shorts, green), (shorts, red), (green, blue), (green, green), (green, red)

The chance he has a green wetsuit and surfboard

Number of outcomes in the sample space with green wetsuit and a green surfboard = 1

number of outcomes in the sample space = 15

The chance he has a green wetsuit and surfboard = (1/15) = 0.0667

Hope this Helps!!!

4 0
3 years ago
If 3/4 = x/8 then x is equal to what
pickupchik [31]

Answer:

x is 6

Step-by-step explanation:

3/4 * x/8

3*8=24 then,

divide by 4 which gives you 6.

Also if you simplify 6/8, it will give you 3/4.

3 0
3 years ago
Read 2 more answers
Find the greatest number that divides451, 328 and 673 leaving 1, 4 and 1,respectively as remainders.
Vesna [10]

You're looking for the largest number <em>x</em> such that

<em>x</em> ≡ 1 (mod 451)

<em>x</em> ≡ 4 (mod 328)

<em>x</em> ≡ 1 (mod 673)

Recall that

<em>x</em> ≡ <em>a</em> (mod <em>m</em>)

<em>x</em> ≡ <em>b</em> (mod <em>n</em>)

is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly

1 ≡ 4 (mod 41)

is not true.

So there is no such number.

4 0
3 years ago
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