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Liono4ka [1.6K]

3 years ago

12

which of the following is the correct point-slope equation for the line that passes through the point (2, -5) and is parallel to

the line given by y = -4x + 25? A. y+5=-4(x-2) B. y-20=-4(x-2) C. y-20=-4x-2 D. y-5=-4(x+2)

1 answer:

lord [1]3 years ago

3 0

Answer:

Step-by-step explanation:

y + 5 = -4(x - 2)

the answer is A

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Find m_ABD and mZCBD given m ABC = 77º. A (3x + 22) D 16 (5x - 17) B C mZ ABD |° and mZCBD

Nostrana [21]

Answer:

∠ ABD = 49°, ∠ CBD = 28°

Step-by-step explanation:

∠ ABD + ∠ CBD = ∠ ABC , substitute values

3x + 22 + 5x - 17 = 77 , that is

8x + 5 = 77 ( subtract 5 from both sides )

8x = 72 ( divide both sides by 8 )

x = 9

Thus

∠ ABD = 3x + 22 = 3(9) + 22 = 27 + 22 = 49°

∠ CBD = 5x - 17 = 5(9) - 17 = 45 - 17 = 28°

4 0

3 years ago

Can someone help me with at least one problem and tell me how you got the answer

Vesna [10]

S=16t^2
if t=3
So you would plug it in
16(3)^2
Then you multipy
16*3^2
=144
It is easier if you use a calculator just type in ti 30 calculator online that should help

4 0

3 years ago

Please help with question 2, I’m too tired to think right now, and it’s for my little sister and it’s due tomorrow! Ignore the n

marishachu [46]

Answer:

2000 L

Step-by-step explanation:

There are 1250 L of water in a tank at present. If the tank is 0.625 full, what is the capacity of the tank?

The simple solution is:

1250 L ÷ 0.625 = 2000 L

The algebraic solution is:

Let <em>c</em> equal the capacity of the tank.

Therefore, <em>c</em> × 0.625 = 1250.

Divide both sides by 0.625:

<em>c</em> × 0.625 ÷ 0.625 = 1250 ÷ 0.625

And simplify:

<em>c</em> = 1250 ÷ 0.625

<em>c</em> = 2000

5 0

3 years ago

In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =

const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

$t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}$

The expression can be simplified as:

$t = 2\sqrt{\frac{h}{16}}$

For a player that has a hang time of 0.9s, the jump is found as follows:

$0.9 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.9}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2$

$h = 16\left(\frac{0.9}{2}\right)^2$

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

$0.8 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.8}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2$

$h = 16\left(\frac{0.8}{2}\right)^2$

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

3 0

2 years ago

If 60 is increased by 90%, what is the new amount?

almond37 [142]

60*.9=54
54+60=114

Hope that helps

4 0

3 years ago

Read 2 more answers