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erastova [34]
3 years ago
10

Find the midpoint of R(-4, 5) and S(3, 3).

Mathematics
2 answers:
maw [93]3 years ago
5 0

The answer would be (-1,2)

arsen [322]3 years ago
4 0

Answer:

you're a creep, so no.

Step-by-step explanation:

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A line passes through the points (1, 4) and (3, –4). Which is the equation of the line?
Vikentia [17]
Y = -4x + 8

First you need to find the slope of the line.

The slope formula is m = y2-y1/x2-x1

If you plugged in the points it would be m = -4-4/3-1

so m = -8/2 = -4

so the slope is -4

now we need to write the equation of the line

for this u use point slope form

the formula for that is y-y2=m(x-x1)

so if you plug it in it would be:

y-(-4)=-4(x-3)

now you solve

y+4=-4x+12

y+4-4= -4x+12-4

y = -4x + 8

and now you have the slope of the line

I hope this helps! :)
5 0
3 years ago
Write the positive or negative integer that this situation represents.
madreJ [45]

Answer:

12

Step-by-step explanation:

A profit, or money you have, or money you deposit in a bank account is usually positive.

A debt, or money you withdraw from a bank account, or money you give away is usually negative.

Answer: 12

5 0
3 years ago
Lines a and b are parallel. The slope of line b is 1/3 . What is the slope of line a?
lesya692 [45]

Answer:

1/3

Step-by-step explanation:

8 0
2 years ago
Triangle ABC , m∠A=45° and c = 16, find b.
zmey [24]

Using the cosine function:

\begin{gathered} \cos (\theta)=\frac{_{\text{ }}adjacent}{_{\text{ }}hypotenuse} \\ so\colon \\ \cos (45)=\frac{b}{16} \end{gathered}

Solve for b:

\begin{gathered} b=16\cdot\cos (45) \\ b=8\sqrt[]{2} \end{gathered}

5 0
1 year ago
Find the domain for the particular solution to the differential equation dy dx equals the quotient of 3 times y and x , with ini
Svetach [21]
For this case we have the following difference equation:
 dy / dx = 3xy

 Applying separable variables we have:
 dy / y = 3xdx

 Integrating both sides we have:
 \int\ ({1/y}) \, dy =  \int\ {3x} \, dx
 ln (y) = (3/2) x ^ 2 + C

 applying exponential to both sides:
 exp (ln (y)) = exp ((3/2) x ^ 2 + C)

 y = C * exp ((3/2) x ^ 2)
 For y (1) = 1 we have:
 C = 1 / (exp ((3/2) * 1 ^ 2))

C = 0.2
 Thus, the particular solution is:
 y = 0.2 * exp ((3/2) x ^ 2)

 Whose domain is all real.
 Answer:
 y = 0.2 * exp ((3/2) x ^ 2)
 Domain: all real numbers
6 0
3 years ago
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