<span>The simplest method to do this is with the vector dot
product. Let the vector A = <9i + 5j> with magnitude √106 be the base
diagonal, and B = <5j + 3k> be the diagonal vector on the side, with
magnitude √34. Then cos θ = (A dot B) divided by the product of the magnitudes.
A dot B =30, so
cos θ = 30 / √(34 x 106)</span>
<span> = 0.4997 ==></span>
<span> θ = 49.19° is the
answer</span>




Divide both sides by -2. We know that since 2 is negative, it'll be < (less than) 0. So, the direction of inequality will change.

Divide 26 by -2..we'll get the answer as -13.

Now, subtract 3 from both the sides.

Subtracting -13 by 3..we'll get the answer as -16.

Divide both sides by 2. We know that since 2 is positive, the direction of inequality will remain the same.

Divide -16 by 2..we'll get the answer as -8.

- The correct answer is ⇨ <u>x </u><u>greater </u><u>than </u><u>or </u><u>equal</u><u> to</u><u> </u><u>-</u><u>8</u><u>.</u>
We're finding the function of (p+3), which means wherever there's an x, we're replacing it with (p+3).
2 (p+3)^2 + 3 (p+3) + 6
Foil out (p+3)^2.
2 (p^2 + 6p + 9) + 3 (p+3) + 6
Distribute.
2p^2 + 12p + 18 + 3p + 9 + 6
Add like terms.
g (p+3) = 2p^2 + 15p + 33