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2 years ago

Help me lawd!!!!!!!jkdmfkfm

Mathematics

1 answer:

Klio2033 [76]2 years ago

6 0

This is equivalent to:

(2.2533/2.59)(10^8/10^4)

(0.87)(10^4) which is:

0.87X10^4 which is equal to:

0.87X10000 which is equal to:

8.7X1000 and since 1000=10^3 we can say:

8.7X10^3

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PLEASE HELP ME!!!! I NEED THIS QUICKLY!!

zloy xaker [14]

Part A: $y=-\frac{5}{4} x+\frac{35}{2}$ is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)$

Substituting, we get,

$y-15=\frac{10-15}{6-2} (x-2)$

Simplifying, we have,

$y-15=-\frac{5}{4} (x-2)$

$y-15=-\frac{5}{4} x+\frac{5}{2}$

Subtracting both sides by 15, we get,

$y=-\frac{5}{4} x+\frac{35}{2}$

Hence, the equation of the line is $y=-\frac{5}{4} x+\frac{35}{2}$

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

$y=\frac{35}{2}\\y=17.5$

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting , we have,

$m=\frac{10-15}{6-2}=-\frac{5}{4}$

Converting the fraction into hours and minutes, we get,

$-\frac{5}{4}\times60=-75 min$

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

6 0

3 years ago

Imagine a population of birds with an initial size of 100, a per-capita birth rate of 2, and a per-capita death rate of 1 per ye

Soloha48 [4]

Answer:

3200

Step-by-step explanation:

Given that:

The initial population of birds $N_0$ = 100

The time duration t = 5 years

Growth rate (r) = (Birth - Death) rate

= 2 - 1

= 1 / year

∴

using the discrete-time form:

$N_t = N_o (1 + r )^t$

$N_t = 100 (1 + 1 )^5$

$N_t = 100 (2 )^5$

$N_t = 100 \times 32$

$N_t = 3200$

8 0

2 years ago

Find the angel x in d diagram above with a well structured solution.<br><br>Thanks

Tom [10]

Step-by-step answer:

Please refer to attached image.

1. Quad PQRS is cyclic (all vertices on the same circle), so opposite angles are supplementary, meaning

that

angles QPS and QRS are supplementary =>

QPS+QRS=180 =>

QRS = 180 - 74 = 106

2. Triangle RSQ is isosceles with RS=RQ =>

angles RSQ and RQS are congruent.

3. Angle RSQ = (180 - 106) /2 = 74 / 2 = 37

4. QP is a diameter => angle QSP is a right-angle.

5. From (3) and (4) above,

angle RSP = 37+90 = 127

6. Since PQRS is cyclic, angles RQP and RSP are supplementary =>

RQP+RSP = 180 =>

x + 127 = 180 =>

x = 180 - 127 = 53 degrees.

5 0

3 years ago

A weather service records 28.8 inches of rain over a 12 month period. What is the average rainfall per month for the year?

Basile [38]

Answer:

B) 2.4 inches

Step-by-step explanation:

The total amount of rain is 28.8 inches over 12 months. To find how much rain falls averagely in <em>one </em>month you need to divide the total by the amount of months. 28.8/12 = 2.4

6 0

2 years ago

A ball is dropped from a height of 14 ft. The elasticity of the ball is such that it always bounces up one-third the distance it

Korvikt [17]

Answer:

Hello,

742/27 (ft)

Step-by-step explanation:

$h_1=14\\\\h_2=\dfrac{14}{3} \\\\h_3=\dfrac{14}{9} \\\\h_4=\dfrac{14}{27} \\\\$

$d=14+2*\dfrac{14}{3} +2*\dfrac{14}{9} +2*\dfrac{14}{27} \\=14*(1+\dfrac{1}{3}+\dfrac{2}{9} +\dfrac{2}{27} )\\=14*\dfrac{53}{27} \\=\dfrac{742}{27} \\$

5 0

3 years ago