1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.
2)The solution for b² - 4b + 4 = 0 is x=2.
<u>Step-by-step explanation</u>:
The general form of quadratic equation is ax²+bx+c = 0
where
- a is the coefficient of x².
- b is the coefficient of x.
- c is the constant term.
<u>To find the roots :</u>
- Sum of the roots = b
- Product of the roots = c
1) The given quadratic equation is m² - 5m - 14 = 0.
From the above equation, it can be determined that b = -5 and c = -14
The roots are -7 and 2.
- Sum of the roots = -7+2 = -5
- Product of the roots = -7
2 = -14
The solution is given by (x-7) (x+2) = 0.
Therefore, the solutions are x=7 and x= -2.
2) The given quadratic equation is b² - 4b + 4 = 0.
From the above equation, it can be determined that b = -4 and c = 4
The roots are -2 and -2.
- Sum of the roots = -2-2 = -4
- Product of the roots = -2
-2 = 4
The solution is given by (x-2) (x-2) = 0.
Therefore, the solution is x=2.
The triangle drawn in the question shows a small single line drawn across two sides of the triangle.
This means that those two sides are equal in length.
Hence, the triangle is an isosceles triangle.
In isosceles triangles, the angles opposite to the equal sides are also equal.
Hence, we know that the two angles other than x is 56°.
The sum of the interior angles of a triangle is 180°
x + 56 + 56 = 180
x = 180 - 56 - 56
x = 180 - 112
x = 68°
Hence, the answer is A.
14 - 16 is -2.
Hope this helped.
Answer:
option A
Step-by-step explanation:
∠WPS +∠OPW = 180 {straight line}
∠WPS +110 = 180
∠WPS = 180 - 110
∠WPS = 70°
∠RWQ + ∠QWT +∠TWU = 180 {straight line}
∠RWQ + 60 + 50 = 180
∠RWQ + 110 = 180
∠RWQ = 180 - 110
∠RWQ= 70°
∠PWU + ∠USP + ∠ WPS = 180 {angle sum property of triangle}
∠PWU + 40 + 70 = 180
∠PWU + 110 = 180
∠PWU = 180 - 110
∠PWU = 70°