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andrew-mc [135]
2 years ago
12

Given the equation 2 Square root (x minus 5) = 2, solve for x and identify if it is an extraneous solution.

Mathematics
1 answer:
Karolina [17]2 years ago
8 0
2 root (x-5)=2

Divide each side by 2 (in order to isolate the square root):
Root (x-5) =1

Square both sides to remove the radical sign:
(x-5)=1

Solve:
x=6

To be sure that it is not an extraneous solution, check the solution by replacing the value for the variable in the equation.

2 root (6-5) = 2

The square root of 1 is 1.

2(1)=2
This is correct.
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Help me decrease 25 by 30%
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Step-by-step explanation:

Percentage decrease = 30% × 25

New value = 25 - Percentage decreaseNew value =

25 - Percentage decrease =

25 - (30% × 25) =

25 - 30% × 25 =

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(100% - 30%) × 25 =

70% × 25 =

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Absolute change (actual difference) =

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8 0
2 years ago
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3) What is the shape of the graph of the equation y = 5x – 2?​
german

Answer:

  • Line

Step-by-step explanation:

The equation y = 5x - 2 is slope-intercept form of linear function.

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6 0
3 years ago
192 beads
nirvana33 [79]

Answer:

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b + n = 192

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8 0
3 years ago
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Step-by-step explanation:

+ Both equations

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6 0
3 years ago
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option b is a function.
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6 0
3 years ago
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