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3 years ago

I don't understand please help quickly

Mathematics

1 answer:

larisa [96]3 years ago

7 0

0.07 for me I broke it down to 3/6 divided by 7/1

I'm pretty sure I'm right if not I really apologize

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79,81,84,88,100,88,82 what is the median of these numbets

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84 is the median of the numbers

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3 years ago

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fomenos

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Step-by-step explanation:

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2 years ago

Please determine if the relationship is linear, exponential, or quadratic. justify your answer.

r-ruslan [8.4K]

Answer:

This function is a quadratic.

Explanation:

If you sketch a graph, you will see the points form a U, representing a quadratic function.

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2 years ago

Please help, I’ll give brainliest UwU

umka2103 [35]

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Step-by-step explanation:

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2 years ago

A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner

frozen [14]

Answer:

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner $I_{corner}$ is:

$I_{corner} = \int\limits \int\limits_R (x^2+y^2) \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx$

where :

(a and b are the length and the breath of the rectangle respectively )

$I_{corner} = \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx$

$I_{corner} = \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx$

$I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}$

$I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]$

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Thus; the moment of inertia of the lamina about one corner is $I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

7 0

2 years ago

I don't understand please help quickly​

I don't understand please help quickly