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densk [106]
3 years ago
8

Jack is practicing pitching with his team. He rotates pitching with his teammates after 12 pitches thrown. He has to throw at le

ast 50 strikes before he can leave. How many rotations must Jack at least make if he throws 14 balls?
Mathematics
1 answer:
vitfil [10]3 years ago
4 0

Step-by-step explanation:

You might be interested in
What is the value of the following expression? <br> 4×[6+(27÷3)+11]
-BARSIC- [3]
4 × (6+7 + 11)
4 × 24
96
4 0
3 years ago
Read 2 more answers
Jake and Seth put some money into their money boxes every week. The amount of money (y), in dollars, in their money boxes after
Maru [420]
1)  How many weeks will Jake and Seth be equal? set the equations equal to each other and solve for x:

5x + 85 = 20x + 40

45 = 15x

<u><em>x = 3 weeks</em></u>

2)  How much money will that be? plug x = 3 back into the equation to solve for y:

Jake:  5(3) + 85 = $100
Seth:  20(3) + 40 = $100

<u><em>answer is $100</em></u>
4 0
3 years ago
High school math help please (20 points for 3 problems, but if you could even answer 2 that would help. Please explain how you g
ipn [44]

Answer:

To question 1: van=9, bus=60

To question 2: Sorry, I don't know the answer.

To question 3: skate rental fee=$2.50, admission fee=$3.25

Step-by-step explanation:

Question 1:

Step 1 - set up equations

14v+16b=1,086

10b+13n=870

Step 2 - Solve for variable (in this case v)

10v+13b=870

Subtract 13b from both sides

10v=-13b+870

Divide both sides by 10

V=-1.3b+87

Step 3 - substitute the v in equation and solve

14 (-1.3b+87)+16b=1,086

-18.2b+1,218+16b=1,086

Combine like-terms

-2.2b+1,218=1,087

Subtract 1,218 from both sides

-2.2b=-132

Divide both sides by -2.2

B=60

Step 4 - substitute for b and solve

10v+13(60)=870

10v+780=870

Subtract 780 from both sides

10v=90

Divide both sides by 10

V=9

Question 3:

Step 1 - set up equations

5s+6f=32

5s+7f=35.25

Step 2 - solve for variable (in this case s)

5s+6f=32

Subtract 6f from both sides

5s=-6f+32

Divide both sides by 5

S=-1.2f+6.4

Step 3 - substitute for s and solve

5(-1.2f+6.4)+7f=35.25

-6f+32+7f=35.25

Combine like-terms

F+32=35.25

Subtract 32 from both sides

F=3.25

Step 4 - substitute for f

5s+6(3.25)=32

5s+19.5=32

Subtract 19.5 from both sides

5s=12.5

Divide both sides by 5

S=2.5

4 0
3 years ago
PLEASE ANSWER QUICK! I REALLY NEED HELP!
Katarina [22]

Answer:

a) Angle 1 = Value in degree = 95°

b)Angle 2 = Value in degree = 77°

c) Angle 3 = Value in degree = 85°

d) Angle 4 = Value in degree = 103°

Step-by-step explanation:

We use circle theorems to solve for this above question.

a) Angle 1 = Value in degree = 95°

Inscribed Angle is 1/2 of an Intercepted Arc

From the diagram, Angle 1 intersects at Arc B and Arc C

This means Angle 1 = (B + C)/ 2 =

Arc B = 100°

Arc C = 90°

Angle 1. = (100° + 90°)/ 2 = 190/ 2 = 95°

b)Angle 2 = Value in degree = 77°

From the diagram, Angle 2 intersects at Arc C and Arc D

Inscribed Angle is 1/2 of an Intercepted Arc

This means Angle 1 = (C+ D)/ 2

C = 90°

D = 64°

Angle 1. = (90° + 64°)/ 2 = 154/ 2 = 77°

c) Angle 3 = Value in degree = 85°

From the diagram, we can see that Angle 1 is opposite Angle 3, hence,

Opposite angles are supplementary which means their addition = 180°

Mathematically:.Angle 1 + Angle 3 = 180°

Angle 1 = 95°

95° + Angle 3 = 180°

Angle 3 = 180° - 95° = 85°

d) Angle 4 = Value in degree = 103°

From the diagram, we can see that Angle 2 is opposite Angle 4,

Hence,

Opposite angles are supplementary which means their addition = 180°

Mathematically:.Angle 2 + Angle 4 = 180°

Angle 2 = 77°

77° + Angle 3 = 180°

Angle 4 = 180° - 77° = 103°

4 0
3 years ago
Express into partial fractions 3x³ - 5x² - 3x - 40/( x² + 4)(x - 3)​
Fudgin [204]

First simplify the rational expression by dividing. The degree in the numerator has to be at least 1 less than the degree in the denominator before you can decompose into partial fractions.

(3<em>x</em>³ - 5<em>x</em>² - 3<em>x</em> - 40) / ((<em>x</em>² + 4) (<em>x</em> - 3)) = 3 + (4<em>x</em>² - 15<em>x</em> - 4) / ((<em>x</em>² + 4) (<em>x</em> - 3))

Now decompose the remainder term into partial fractions:

(4<em>x</em>² - 15<em>x</em> - 4) / ((<em>x</em>² + 4) (<em>x</em> - 3)) = (<em>ax</em> + <em>b</em>) / (<em>x</em>² + 4) + <em>c</em> / (<em>x</em> - 3)

Multiply both sides by the denominator on the left:

4<em>x</em>² - 15<em>x</em> - 4 = (<em>ax</em> + <em>b</em>) (<em>x</em> - 3) + <em>c</em> (<em>x</em>² + 4)

Expand the right side:

4<em>x</em>² - 15<em>x</em> - 4 = <em>ax</em>² + (<em>b</em> - 3<em>a</em>) <em>x</em> - 3<em>b</em> + <em>cx</em>² + 4<em>c</em>

4<em>x</em>² - 15<em>x</em> - 4 = (<em>a</em> + <em>c</em>) <em>x</em>² + (<em>b</em> - 3<em>a</em>) <em>x</em> - 3<em>b</em> + 4<em>c</em>

Then

<em>a</em> + <em>c</em> = 4

<em>b</em> - 3<em>a</em> = -15

-3<em>b</em> + 4<em>c</em> = -4

Solve this system to get

<em>a</em> = 5, <em>b</em> = 0, <em>c</em> = -1

We end up with

(4<em>x</em>² - 15<em>x</em> - 4) / ((<em>x</em>² + 4) (<em>x</em> - 3)) = 5<em>x</em> / (<em>x</em>² + 4) - 1 / (<em>x</em> - 3)

and so

(3<em>x</em>³ - 5<em>x</em>² - 3<em>x</em> - 40) / ((<em>x</em>² + 4) (<em>x</em> - 3))

= 3 + 5<em>x</em> / (<em>x</em>² + 4) - 1 / (<em>x</em> - 3)

8 0
3 years ago
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