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blondinia [14]
3 years ago
15

Mary is n years old. What expression represents her age 5 years from now? 5 years ago?

Mathematics
1 answer:
MissTica3 years ago
3 0

Answer:

After 5 years : <em>(</em><em> </em><em>n</em><em> </em><em>+</em><em> </em><em>5</em><em> </em><em>)</em><em> </em><em>years</em><em> </em><em>!</em>

<em>Before </em><em>5</em><em> </em><em>years</em><em> </em><em>:</em><em> </em><em>(</em><em> </em><em>n</em><em> </em><em>-</em><em> </em><em>5</em><em> </em><em>)</em>

Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u>the </u></em><em><u>age</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>Mary</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em> </em><em>n</em><em> </em><em>years</em><em> </em><em>old</em><em> </em>

<em>After</em><em> </em><em>5</em><em> </em><em>years</em><em> </em><em>,</em><em> </em><em>She</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>5</em><em> </em><em>years</em><em> </em><em>more</em><em> </em><em>from</em><em> </em><em>now</em><em> </em><em> </em><em>so</em><em>,</em><em> </em>

<em>Her</em><em> </em><em>age</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em> </em><em>(</em><em> </em><em>n</em><em> </em><em>+</em><em> </em><em>5</em><em> </em><em>)</em><em> </em><em>years</em><em> </em><em> </em><em>after</em><em> </em><em>5</em><em> </em><em>years</em><em> </em><em>from</em><em> </em><em>now</em><em> </em><em>!</em>

<em>Also</em><em>,</em><em> </em><em>5</em><em> </em><em>years</em><em> </em><em>ago</em><em> </em><em> </em><em>she</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>5</em><em> </em><em>y</em><em>ears</em><em> </em><em>less</em><em> </em><em>than</em><em> </em><em>from</em><em> </em><em>now</em><em> </em><em>,</em>

<em>So</em><em>,</em><em> </em><em>her</em><em> </em><em>age</em><em> </em><em>5</em><em> </em><em>y</em><em>ears</em><em> </em><em>ago</em><em> </em><em>was</em><em> </em><em>(</em><em> </em><em>n</em><em> </em><em>-</em><em> </em><em>5</em><em> </em><em>)</em><em> </em><em>years</em><em> </em><em>!</em><em> </em>

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Answer:

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Step-by-step explanation:

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Right now, though, we only need to focus on the slope. The slope represents a change in y over a change in x. Our y-values represent <em>total amount saved</em>, and our x-values represent <em>number of weeks</em>. Y over x... so, total amount saved over a certain number of weeks.

The first answer seems to match this the best. Remember that the slope represents how much is saved per week, and our slope is 17.63. So, the first answer (Aidan can expect to save about $17.63 each week) is correct. If you have any more questions or that was confusing at all, let me know! :)

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-52 times the difference a number and 97 is equal to the number plus 39
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-52 (x - 97) = x + 39

-52x + 5,044 = x + 39
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Answer:

The 99% confidence interval is (0.0787, 0.1613).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

The survey included 411 adults between the ages of 55 and 64, and 50 of them said that they had used online dating. This means that n = 411, \pi = \frac{50}{411} = 0.12

The 99% confidence interval is

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{411}} = 0.12 - 2.575\sqrt{\frac{0.12*0.88}{411}} = 0.0787

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{411}} = 0.12 + 2.575\sqrt{\frac{0.12*0.88}{411}} = 0.1613

The 99% confidence interval is (0.0787, 0.1613).

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