The graphs of the functions f and g are shown above. If
Bg%28x%29%2B2x%7D" id="TexFormula1" title="h(x)=\frac{f(x)+4}{g(x)+2x}" alt="h(x)=\frac{f(x)+4}{g(x)+2x}" align="absmiddle" class="latex-formula">, then h′(3)=
1 answer:
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Answer:
Answer is in photo
Answer:
C and A
Step-by-step explanation:
For the triangle to be isosceles then the legs are congruent, that is
XZ = XY , substitute values
5x - 1 = 3x + 5 ( subtract 3x from both sides )
2x - 1 = 5 ( add 1 to both sides )
2x = 6 ( divide both sides by 2 )
x = 3 → C
(10)
The diagonals of a square bisect each other
Calculate PR using the distance formula
d =
with (x₁, y₁ ) = P(0, 0) and (x₂, y₂ ) = R(6, - 8)
PR =
=
=
=
= 10
Then
PT = 0.5 × 10 = 5 → A
Compare to the vertex form of parabola
- y=a(x-h)^2+k
- h=-2
- k=-1
So vertex should be at (h,k)=(-2,-1)
Graph attached
