Pleaseeee help meeeeeee

The length and width of a rectangle are consecutive integers. The perimeter of the

Hunter-Best [27]

The length of the rectangle is 9 feet and the width of the rectangle is 10 feet.

<h3>What is the Perimeter of a Rectangle?</h3>

The sum of a rectangle's boundary lengths on all sides is known as its perimeter. A rectangle's perimeter is a linear measurement that can be expressed in meters, feet, inches, or yards. Let's first comprehend the two fundamental characteristics of a rectangle.

A rectangle has four 90° angles.
The lengths of a rectangle's diagonals are equal.

Let the length of the rectangle be x feet

Then, the width of the rectangle will be x+1feet

We know that the perimeter of a rectangle is given by

P= 2(l+w)

Here

P= perimeter of a rectangle

l=length of the rectangle

w= width of the rectangle

Put l=x, w= x+1 and P= 38 in the perimeter formula

38 = 2(x+x+1)

Divide both sides by 2

19= x+x+1

19= 2x+1

Subtract 1 from both sides

18=2x

Divide both sides by 2

x=9 feet

This is the length of the rectangle.

Now, the width x+1 of the rectangle will be

9+1 = 10 feet

To know more about the perimeter of a rectangle, visit:

brainly.com/question/2142493

#SPJ9

5 0

1 year ago

One of the parking lot lights at a hospital has a motion detector on it, and the equation (x+10)2+(y−8)2=16 describes the bounda

Pani-rosa [81]

We are given an equation:
$(x+10)^{2} + (y-8)^{2} = 16$

This is an equation of a circle. General form of a circle equation is:
$(x-a)^{2} + (y-b)^{2} = r^{2}$
Where:
a = x coordinate of a center
b = y coordinate of a center
r = radius of a circle

Motion detector can detect person anywhere within a boundary. The greatest distance at which detector can detect is at the edge of a circle. That distance, between detector and edge of circle, is equal to radius.

From the equation we have:
$r^{2} =16 \\ r=4$
The greatest distance at which person can be detected is 4ft.

7 0

3 years ago

Read 2 more answers

Which of the following pairs of lines are not parallel?

goldfiish [28.3K]

Answer: Not sure

Step-by-step explanation: A is wrong because they are parallel in one is on the top to the right and 1 is on the bottom. sorry thats all i know :(

7 0

2 years ago

Which congruence statements are true? Choose all answers that are correct?<br><br> A: B: C: D:

tester [92]

Answer:

Correct choices are A and C

Step-by-step explanation:

Inscribed angles property: The inscribed angles subtended by the same arc are equal.

1. Angles EFH and EGH are both inscribed angles subtended by the arc EH. Therefore, these angles are congruent (option A is true).

2. Angles GHF and GEF are both inscribed angles subtended by the arc GF. Therefore, these angles are congruent (option C is true).

3. Angles EGH and FHG are interior angles of the triangle KGH and can be congruent (if triangle is isosceles) or can be not congruent (in general). Thus, option B is false.

4. Angles EFH and FHG in general are not congruent. They can be congruent only when arcs EH and FG have the same measure. In general, option D is false.

4 0

3 years ago

Please help me answer one of these!

babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.

There aren't any parallel lines involved in the above described construction, so I'll skip the first one.

2. Why do the circles have to be congruent ...

The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.

3. ... circles of different sizes ...

[We just answered that. Let's do it again.]

Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.

4. ... construct the perpendicular bisector ... a different way?

Maybe what I first described is different; there are no parallel lines.

8 0

3 years ago