It doubles every 4 hours, so after 24 hours there will be 6 doublings.
2^6 = 64
So, the population will be (3,000,000 * 64) or 192,000,000 in 24 hours.
The answer is B.
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
Initial Amount=1
Decay Factor=0.99987
Decay Rate=0.013%
Step-by-step explanation:
If P = 0.99987ᵃ
I. Initial amount
The initial amount is when a=0
P = 0.99987⁰ = 1
The Pressure at Sea Level=1
II. Decay factor
This is like the decay constant. From the model, P = 0.99987ᵃ, the decay constant/factor is 0.99987.
III. Decay Rate = 1-0.99987 = 0.00013
Expressed in Percentage = 0.013%
1) the small and large triangles are similar, then we can write:
x/24 = 8/18
Cross multiplication → 18x = 24.8 → 18x = 192 and x = 192/18
and x = 32/3 Or 10 ²/³
2) Δ ABC is similar to Δ EDC Since:
∠A = ∠D = 90°
∠C is common
