Answer:
(a) Verified
(b) They are simultaneous equations
Step-by-step explanation:
Given
Required
Verify that: 
is a solution
We have:
Substitute:
Evaluate all products
Subtract:
<em>Because both sides of the equation are equal, then the point is a solution</em>
<em></em>
Also:
Substitute:
Evaluate all products
Subtract:
<em>Because both sides of the equation are equal, then the point is a solution</em>
<em></em>
<em></em>
Because the given point is a solution to both equations, then they are simultaneous equation
Value of x is 10
Step-by-step explanation:
- Step 1: Here, x is the hypotenuse of the right angled triangle. Use the trigonometric ratio cosine to find x.
cos 28° = adjacent side/hypotenuse = 11/x
⇒ x = 11/cos 28° = 11/-0.96 = -11.46 ≈ 10 (rounding off to nearest tenth)
7/5 * 5/7y = 7/5 * 6
y = 42/5.
The multiplication property of equality is used.
9a^2 -6ab+ 12ac -8bc
This expression cannot be factorized because its terms don't have at least a common factor~
Answer:
The coordinates of the image trapezoid are
A"(-4,5), B''(-1,5), C''(0,3), D''(-5,3)
The pre-image was first reflected in the line y=x, so the mapping will be
The resulting coordinates were then translated 4 units right;
For A''(-4,5), y+4=-4 and x=5
This means y=-8, x=5
Hence A(5,-8)
For B''(-1,5), y+4=-1, and x=5.
This means y=-5 and x=5
B(5,-5)
For C''(0,3), C(3,-4)
For D''(-5,3), D(3,-9)
Step-by-step explanation:
there u go
