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4 years ago

5

Mary has 50 earring boxes the boxes measure 1 inch on each side how many rectangular prisms each with a different sized base cou

ld mary make by stacking all of the earring boxes

1 answer:

Ann [662]4 years ago

4 0

Given:
50 earring boxes with a measure of 1 inch each side

volume of boxes = a³ = 1³ = 1 in³
total volume of boxes = 1 in³ * 50 boxes = 50 in³

volume of a rectangular prism = length * width * height
50 in³ = length * width * height

Let us assume that the height is 1 in.

length and width can be factored:
50 x 1
25 x 2
10 x 5

I can only make 3 rectangular prisms

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324.5 as scientific notation;<br><br> step by step explanation please

dlinn [17]

Answer:

3.456 x 10^11

Step-by-step explanation:

= 3.456 × 10¹¹

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3 years ago

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What are the first three terms of a geometric sequence in which as = 25 and the common ratio is 5?

marin [14]

Answer:

The first three terms are: 25, 125 and 625

Step-by-step explanation:

Given

$a =25; r = 5$

Required

The first three terms

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$T_n =ar^{n-1$

So, we have:

First term: $n = 1$

$T_n =ar^{n-1$

$T_1 =25 * 5^{1-1$

$T_1 =25 * 5^0$

$T_1 =25 * 1$

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Second term: $n = 2$

$T_n =ar^{n-1$

$T_2 =25 * 5^{2-1$

$T_2 =25 * 5^{1$

$T_2 =25 * 5$

$T_2 =125$

Third term: $n = 3$

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$T_3 =25 * 5^{3-1$

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3 years ago

Which of the following best describes a plane ?

leonid [27]

The best example of a plane would be A) the surface of a flat table. A plane could also be represented by anything that is flat in nature.

Hope this helps! :)

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4 years ago

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Vsevolod [243]

Answer:

The margin of error is 6.45.

Step-by-step explanation:

The complete question is:

As an early intervention effort, a school psychologist wants to estimate the average score on the Stanford-Binet Intelligence Scale for all students with a specific type of learning disorder using a simple random sample of 36 students with the disorder.

Determine the margin of error, of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume that the standard deviation IQ score among the population of all students with the disorder is the same as the standard deviation of IQ score for the general population, σ = 15 points.

The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

$CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

Given:

<em>n</em> = 36

σ = 15

(1 - <em>α</em>)% = 99%

Compute the critical value of <em>z</em> for 99% confidence level as follows:

$z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$

*Use a <em>z</em>-table.

Compute the value of MOE as follows:

$MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}$

$=2.58\times\frac{15}{\sqrt{36}}$

$=2.58\times 2.5\\=6.45$

Thus, the margin of error is 6.45.

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3 years ago

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balu736 [363]

Answer:

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Step-by-step explanation:

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4 years ago

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