Answer:
C AND D
Step-by-step explanation:
it is a rational and real number
Answer:
2x – 4 – 1 + x
Step-by-step explanation:
Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:

Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

That's 1/4 of a minute which is 15 seconds.
<em>3</em><em>9</em><em>></em><em>3</em><em>8</em>
<em>1</em><em>6</em><em>=</em><em>1</em><em>6</em>
<em>1</em><em>1</em><em><</em><em>3</em><em>1</em><em>5</em>
<em>5</em><em>></em><em>4</em>
<em>Hope </em><em>this </em><em>helps </em><em>you </em><em>mate </em>
<em>~♥~</em><em>♪☆\(^0^\) ♪(/^-^)/☆</em><em>♪☆\(^0^\) ♪(/^-^)/☆</em><em>♪\(*^▽^*)/\(*^▽^*)/</em><em>♪☆\(^0^\) ♪(/^-^)/☆</em><em>♪ ♬ ヾ(´︶`♡)ノ ♬ ♪</em>